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777dan777 [17]
3 years ago
7

which scale drawing of the parallelogram has a scale factor of 1/3 if the original parallelogram has lengths 6 cm and 15 cm​

Mathematics
2 answers:
irinina [24]3 years ago
6 0

Answer:

2 and 5

Step-by-step explanation:

ololo11 [35]3 years ago
5 0

don’t quote me but 2 and 5 cm?

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What are two subsets of real numbers that form the set of real numbers
Ulleksa [173]

Answer:

Two subsets that form set of real numbers

You can take positive numbers and negative numbers subset

One subset become (- infinity,0]

other subset (0, infinity)

4 0
3 years ago
Toby's Tiny Toys have fixed expenses of $53,900 for the production of their tiny toys. Toby's has a variable expense of $12.50 a
ipn [44]

The total cost of the factory will be the sum of its variable costs and it's fixed costs. The factory has fixed costs of $53,900 and variable costs of $12.50 per unit produced. Let x be the number of toy's produced by this Toby's Tiny Toys, then the total variable costs will be 12.50x. From this information we can gather that the cost function for this factory is,

C(x)=53\,900+12.50x.

On the other hand, if we let x be the number of toys sold, we can gather that at the selling price of 16.50, the revenue function will be ,

R(x)=16.50x.

Toby's Tiny Toys will reach their break even point when the total costs are equal to the total revenue. At this break even point ,we have that

R(x)=C(x)\\\implies 16.50x=12.50x+53\,900\\\implies 16.50x-12.50x=53\,900\\\implies 4x=53\,900\\\implies x=\frac{53\,900}{4} \\\implies x=134\,750.

The company has to sell 134 750 units to break even.

6 0
4 years ago
Plz someone help meeeee
yan [13]

Answer:

s ur e eye ge

Step-by-step explanation:

the answer is y = (6, 0) quadrant 1

3 0
3 years ago
use a graphing calculator or other technology to answer the question which quadratic regression equation best fits the data set
Greeley [361]

Answer:

Option C is the correct option.

In other words, the quadratic regression y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\: best fits the data set, as it gets very much close to the data values given in the data table.

The graph of the equation  y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:  is also attached.

Step-by-step explanation:

x                 y

3                470

4                416

5                403

Analyzing Option A:

Considering the equation

y=32.86\:\left(x\right)^2+379.14\left(x\right)-1369.14\:

From (3, 470), putting x = 3

y=32.86\:\left(3\right)^2+379.14\left(3\right)-1369.14\:

y=64.02

From (4, 470), putting x = 4

y=32.86\:\left(4\right)^2+379.14\left(4\right)-1369.14\:\:

y=673.18

From (5, 403), putting x = 5

y=32.86\:\left(5\right)^2+379.14\left(5\right)-1369.14\:

y=1348.06

Analyzing Option B:

y=32.86\:\left(x\right)^2-379.14\left(x\right)

From (3, 470), putting x = 3

y=32.86\:\left(3\right)^2-379.14\left(3\right)

y=-841.68

From (4, 470), putting x = 4

y=32.86\:\left(4\right)^2-379.14\left(4\right)

\:y=-990.8

From (5, 403), putting x = 5

y=32.86\:\left(5\right)^2-379.14\left(5\right)

\:y=-1074.2

Analyzing Option C:

Considering the equation

y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:

From (3, 470), putting x = 3

y=32.86\:\left(3\right)^2-379.14\left(3\right)+1369.14\:

y=527.46

So, the approximately result is (3, 527)

From (4, 470), putting x = 4

y=32.86\:\left(4\right)^2-379.14\left(4\right)+1369.14\:

y=378.34

So, the approximately result is (4, 378)

From (5, 403), putting x = 5

y=32.86\:\left(5\right)^2-379.14\left(5\right)+1369.14\:\:\:

y=294.94

So, the approximately result is (5, 295)

Analyzing Option D:

Considering the equation

y=-1369.14\:\left(x\right)^2-379.14\left(x\right)+32.86

From (3, 470), putting x = 3

y=-1369.14\:\left(3\right)^2-379.14\left(3\right)+32.86\:\:

y=-13426.82

From (4, 470), putting x = 4

y=-1369.14\:\left(4\right)^2-379.14\left(4\right)+32.86

y=-23389.94

From (5, 403), putting x = 5

y=-1369.14\:\left(5\right)^2-379.14\left(5\right)+32.86\:\:

y=-36091.34

Therefore, from the above calculations and analysis, we conclude that Option C is the correct option.

In other words, the quadratic regression y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\: best fits the data set, as it gets very much close to the data values given in the data table.

The graph of the equation  y=32.86\:\left(x\right)^2-379.14\left(x\right)+1369.14\:  is also attached.

3 0
3 years ago
The number 0.09 has a value greater than 0.009 am i correct
aniked [119]
0.09 is nine hundredths.

0.009 is nine thousandths.

You are correct.
6 0
3 years ago
Read 2 more answers
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