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3 years ago

Solve for m and n using the special right triangles

Mathematics

1 answer:

Irina18 [472]3 years ago

8 0

Since this is a 45-45-90 triangle, n = 6 and m = 6√3.

I hope this helps!

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HELP IVE BEEN STRUGGLING FOR THE PAST 15 MIN PLEASEEEEE

joja [24]

Answer:

c= -1/2

Step-by-step explanation:

Let's solve your equation step-by-step.

4 /3 = −6c − 5/ 3

Step 1: Simplify both sides of the equation.

4 /3 =−6c + −5 /3

Step 2: Flip the equation.

−6c + −5 /3 = 4/3

Step 3: Add 5/3 to both sides.

−6c + −5 /3 + 5 /3 = 4/3 + 5 /3 −6c

Step 4: Divide both sides by -6.

−6c −6 = 3 − 6 c = −1 /2

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3 years ago

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2. 2(x+1.25) = 3.5

dangina [55]

Answer:

x = 0.5

Step-by-step explanation:

Given

2(x + 1.25) = 3.5 ← divide both sides by 2

x + 1.25 = 1.75 ( subtract 1.25 from both sides )

x = 0.5

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3 years ago

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(08.01 MC)Below are the data collected from two random samples of 500 American adults on the number of hours they spend doing le

Mazyrski [523]

Answer:

Dan is correct

Step-by-step explanation:

From the question, we have:

$Hours:1\ 2\ 3\ 4\ 5$

Required

The average

The average hour is calculated using:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{1+2+3+4+5}{5}$

$\bar x = \frac{15}{5}$

$\bar x = 3$

Dan calculated the mean as 3; while Bret calculated the mean as 4.

Hence, we can conclude that Dan s correct

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2 years ago

Hey how do you get from standard form to vertex form?

vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be $\mathbf{ax^{2}+bx+c=0}$ where x is the variable.

Completing the square method is as follows:

send the constant term to other side of equal $\mathbf{ax^{2}+bx=-c}$
divide the whole equation be coefficient of $\mathbf{x^{2}}$ , this will give $\mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}$
add $\mathbf{(\frac{b}{2a})^{2}}$ to both side of equality $\mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}$
Make one fraction on the right side and compress the expression on the left side $\mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}$
rearrange the terms will give the vertex form of standard quadratic equation $\mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}$