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Dafna11 [192]
3 years ago
6

Solve for m and n using the special right triangles

Mathematics
1 answer:
Irina18 [472]3 years ago
8 0
Since this is a 45-45-90 triangle, n = 6 and m = 6√3.

I hope this helps!
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HELP IVE BEEN STRUGGLING FOR THE PAST 15 MIN PLEASEEEEE
joja [24]

<u>Answer:</u>

c=  -1/2

<u>Step-by-step explanation:</u>

Let's solve your equation step-by-step.

4 /3  = −6c − 5/ 3

Step 1: Simplify both sides of the equation.

4 /3  =−6c +  −5 /3

Step 2: Flip the equation.

−6c +  −5 /3  =  4/3

Step 3: Add 5/3 to both sides.

−6c +  −5 /3  +  5 /3  = 4/3  +  5 /3  −6c

=3

Step 4: Divide both sides by -6.

−6c  −6   =  3 − 6 c =  −1 /2

4 0
3 years ago
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2. 2(x+1.25) = 3.5
dangina [55]

Answer:

x = 0.5

Step-by-step explanation:

Given

2(x + 1.25) = 3.5 ← divide both sides by 2

x + 1.25 = 1.75 ( subtract 1.25 from both sides )

x = 0.5

8 0
3 years ago
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(08.01 MC)Below are the data collected from two random samples of 500 American adults on the number of hours they spend doing le
Mazyrski [523]

Answer:

Dan is correct

Step-by-step explanation:

From the question, we have:

Hours:1\ 2\ 3\ 4\ 5

Required

The average

The average hour is calculated using:

\bar x = \frac{\sum x}{n}

So, we have:

\bar x = \frac{1+2+3+4+5}{5}

\bar x = \frac{15}{5}

\bar x = 3

<em>Dan calculated the mean as 3; while Bret calculated the mean as 4.</em>

<em>Hence, we can conclude that Dan s correct</em>

4 0
2 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

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3 years ago
Y= -1.4 -1 x intercept?
eimsori [14]

Answer:

b = -1.4

Step-by-step explanation:

5 0
2 years ago
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