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2 years ago

6

Two months ago, the price, in dollars, of a cell phone was c.

1 answer:

laiz [17]2 years ago

5 0

Answer:

c × 0.90

Step-by-step explanation:

c × 0.90, would be your answer because 10% is equal to 0.10, then you would subtract the 0.10 (10%) by 1 (100%), then multiply c times the 0.90 that you get, to get the decreased number, because you're multiplying by a decimal

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How to find the rate of change of the inputs

iogann1982 [59]

Answer:

To find the average rate of change, we divide the change in the output value by the change in the input value.

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3 years ago

A factory made 845 pairs of shoes in January. These shoes were sent to three shoe stores and one outlet mall. The number of pair

Semenov [28]

Answer=65 pairs of shoes

Given the data, the following equation can be made where x is equal to the number of shoes sent to the outlet mall.

845=4x+4x+4x+x
845=13x
divide both sides by 13
65=x

65 pairs of shoes were sent to the outlet mall

7 0

3 years ago

Read 2 more answers

What domain, range, median, and mode?

omeli [17]

I don't know domain but range is the smallest number and largest number, median is the middle number when the numbers are ordered from least to greatest, and the mode is the most common or reoccuring variable in a set of numbers.

6 0

3 years ago

The year the Greek city of Helike disappeared is -1/5 times the year the US civil war ended. Let w represent the year the war en

Lostsunrise [7]

Answer:

ok so

-1/5x=w

w=1865

so -1/5x=1865

x=-9325

Hope This Helps!!!

5 0

2 years ago

Read 2 more answers

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

3 years ago