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pishuonlain [190]
3 years ago
11

A company has two large computers. The slower computer can send all the company's email in 45 minutes. The faster computer can c

omplete the same job in 30 minutes. If both computers are working together, how long will it take them to do the job?
Mathematics
1 answer:
tatuchka [14]3 years ago
7 0

Answer

It would take them the same amount of time as it normally took.

Which would be 30 and 45 minutes.

please feel free to ask me some more questions, or clarify.

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An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different ti
Simora [160]

Answer:

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 ....... Equation 1

95 E + 110W = 400  ......Equation 2

Hence,

An Eastbound train has been travelling for =  (E) = 2.67 hours

A Westbound train has been travelling for =  (W) = 1.33 hours

Step-by-step explanation:

An Eastbound train (E) traveling 95 mph and a Westbound train (W) traveling 110 mph leave the same train station at different times. After 4 hours, they are 4 00 miles apart. Which system of linear equations can be used to determine the time that each of the trains has been traveling?

Speed = Distance/Time

Distance = Speed × Time

Let the time

An Eastbound train =  (E)

A Westbound train =  (W)

E + W = 4 hours ....... Equation 1

95mph × E + 110mph × W = 400 miles

95 E + 110W = 400 miles ......Equation 2

The system of linear equations that can be used to determine the time that each of the trains has been traveling is:

E + W = 4 ....... Equation 1

95 E + 110W = 400  ......Equation 2

E = 4 - W

We substitute 4 - W for E in Equation 2

95 (4 - W) + 110W = 400  

380 - 95W + 110W = 400

Collect like terms

95W - 110W = 400 - 380

15W = 20

W = 20/15

W = 1.3333333333 hours

≈ 1.33 hours

E = 4 - W

E = 4 - 1.33 hours

E = 2.67 hours

Therefore,

An Eastbound train has been travelling for =  (E) = 2.67 hours

A Westbound train has been travelling for =  (W) = 1.33 hours

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