Answer:
The value of y is 67°.
Step-by-step explanation:
Here, given that;
BD is parallel to XY. let EF be a transversal line meeting BD at O and XY at P.
now, angle XQF = 67°
now, angle XQF + angle YQF=180° (being linear pair)
or, 67°+angle YQF =180°
or, angle YQF=180°-67°
therefore angle YQF = 113°.
now, angle YQF + angle PQY=180° (being linear pair).
now, 113°+angle PQY = 180°.
or, angle PQY = 180°-113°.
therefore, angle PQY =67°.
again, angle EPD= angle PQY (being corresponding angles).
or, y°= 67°.
Therefore the value of y is 67°.
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>