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2 years ago

All of the quadrilaterals in the shape below are squares. Find the area of the shaded

Mathematics

1 answer:

ArbitrLikvidat [17]2 years ago

6 0

The area if the shaded region is 32. The blue squares area is 36 but the part that’s cut off has an area of 4. 36-4 equals 32. So that’s the answer!

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Use the Side-Splitting Theorem to find the value of x.

spin [16.1K]

<h2>The required "option D. 9.6" is correct.</h2>

Step-by-step explanation:

In given figure,

AD = x, DB = 12, BE = 8 and EC = 10

To find, the value of x = ?

Use the Side-Splitting Theorem,

We know that,

$\dfrac{AD}{DB} =\dfrac{BE}{EC}$

⇒ $\dfrac{x}{12} =\dfrac{8}{10}$

⇒ x = $\dfrac{8 \times 12}{10}$

⇒ x = $\dfrac{96}{10}$

⇒ x = 9.6

∴ The value of x = 9.6

Thus, the required "option D. 9.6" is correct.

4 0

3 years ago

Henry Works in a store where he earns a 3% commission on wverytging he sells.

Doss [256]

Honestly i dont know but i divided 60 BY 3% God help you and I lol sorry!

4 0

3 years ago

K=?<br><br> Can you also explain so I can try it by my self with a similar one.

Genrish500 [490]

Answer:

k = 10.39

Step-by-step explanation:

tangent 30 = opposite side / adjacent side, opposite side = 9, adjacent side = k + 3sqrt3.

tan 30 = 9/(k + 3sqrt3)

0.5774 = 9/(k + 3sqrt3)

k + 3sqrt3 = 15.5885

k = 15.5885 - 3sqrt3

k = 10.392

8 0

3 years ago

Find the greatest common factor of 8a and 6a?

Katyanochek1 [597]

question:

What is the GCF of 6a 8a and 14?

<h2><u>Answer: </u></h2><h3>The common factors for 6,8,14 6 , 8 , 14 are 1,2 .</h3>

5 0

3 years ago

Read 2 more answers

On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

4 years ago