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4 years ago

Evaluate the function g(x)=-2x^2+3x-5 for the input values -2, 0, and 3

Mathematics

1 answer:

Troyanec [42]4 years ago

5 0

Answer:

-19, -5, 22

Step-by-step explanation:

Input into calculator.

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Y is inversely proportional to (x+2)² when x=1, y=2

REY [17]

Answer:

y = 18 / (x + 2)²

Step-by-step explanation:

Inversely proportional

y * (x + 2)² = k

when x=1, y=2

k = 2 * (1 + 2)²

k = 18

-----------------------

y * (x + 2)² = 18

Divide both sides by (x + 2)²

y = 18 / (x + 2)²

6 0

3 years ago

Which measures of central tendency would be affected if the outlier 11 was added to the following set 27,20,34,37,21,42,39

MrRa [10]

Answer:

Median will not be affected by the outlier.

Step-by-step explanation:

With the outlier, the mean will be dragged way down. The median will likely be about the same. Mean is non-resistant to outliers, median is resistant.

Hope this helps!

5 0

3 years ago

Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1

algol [13]

Find the critical points of $f(x,y)$ :

$\dfrac{\partial f}{\partial x}=-2x=0\implies x=0$

$\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12$

All three points lie within $D$ , and $f$ takes on values of

$\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}$

Now check for extrema on the boundary of $D$ . Convert to polar coordinates:

$f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t$

Find the critical points of $g(t)$ :

$\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0$

$\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2$

$\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi$

where $n$ is any integer. There are some redundant critical points, so we'll just consider $0\le t< 2\pi$ , which gives

$t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3$

which gives values of

$\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}$