Answer:
The correct answer is 9 m per 
Step-by-step explanation:
Force is defined by mass of an object times it's acceleration.
Let the mass of the object be m kilograms.
When a force of 30 N acts on a certain object the acceleration of the object is 5 m per 
∴ 30 = m × 5
⇒ m = 6.
If the force is changed to 54 N, let the acceleration of the object be x m per
.
∴ 54 = m × x
⇒ x =
= 9
Thus when the force is 54 N, the acceleration of the object is 9 m per
.
The answer would be approximately 1.98
Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps
The zeros are at -3, 1 and 3