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3 years ago

13

Elouise is creating a rectangular garden in her backyard. The length of the garden is 12 feet. The perimeter of the garden must

be at least 36 feet and no more than 48 feet. Use a compound inequality to find the range of values for the width of the garden.

1 answer:

Citrus2011 [14]3 years ago

5 0

Answer:

Width <= 12

Width >= 6

Step-by-step explanation:

36 <= 2(12) + 2x <= 48

36 <= 24 + 2x

36 - 24 <= 2x

12/2 <= x

x >= 6

24 + 2x <= 48

2x <= 48 - 24

x <= 24/2

x <= 12

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An animal feed to be mixed from soybean meal and oats must contain at least 168 lb of protein, 27 lb of fat, and 14 lb of minera

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Answer:

The animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

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Step-by-step explanation:

The given parameters can be summarized as:

$\begin{array}{cccc}{} & {x} & {y} & {Total} & {Protein} & {70} & {21} & {168} &{Fats}& {9} & {7} & {27} & {Minerals} & {7} & {1} & {14}& {Cost} & {21} & {7} & {} \ \end{array}$

Where: x = Soybeans and y = Oats.

So, the system of equations are:

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The best way to solve this, is using graph

Plot the following equations on a graph, and get the points of intersection:

$70x + 21y = 168$

$9x +7y = 27$

$7x + y = 14$

From the attached graph, we have:

$(x_1,y_1) = (1.636,2.545)$

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$(x_3,y_3) = (2.023,1.256)$

Substitute each of the values of x's and y's in the cost function to get the minimum cost:

$Cost = 21x + 7y$

$(x_1,y_1) = (1.636,2.545)$

$Cost = 21 * 1.636 + 7 * 2.545$

$Cost = 52.171$

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$Cost = 21 * 1.775 + 7 * 1.575$

$Cost = 48.3$

$(x_3,y_3) = (2.023,1.256)$

$Cost = 21 * 2.023 + 7 * 1.256$

$Cost = 51.275$

The values of x and y that gives the minimum cost is:

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3 years ago

Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with

yan [13]

Answer:

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

<em></em>

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, $s_A =$ 12 inches

Height of A, $h_A =$ 8 inches

Side Length of B, $s_B =$ 48 inches

Height of B, $h_B =$ 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

OR

$V_B$ is how many times bigger than $V_A$ ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

$V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}$

Here, base is square, so:

$V=\dfrac{1}{3} \times s^2 \times h$

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$V_A=\dfrac{1}{3} \times s_A^2 \times h_A$

$\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3$

Volume of pyramid B:

$V_B=\dfrac{1}{3} \times s_B^2 \times h_B$

$\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3$

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

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