Utilizando proporciones, hay que el pick-up más grande carga 5250 kg.
- Este problema se resuelve por proporciones, por médio de una regla de três.
El peso que cargan tres pick-ups están en la razón de 2:6:7
- 2 + 6 + 7 = 15.
- O sea, el pick-up menor carga
de el total, que es equivalente a 1500 kg. - El pick-up más grande carga
de el total, que es equivalente a x kg.
La regla de três es:
- 1500 kg
- x kg
Aplicando multiplicación cruzada:
El pick-up más grande carga 5250 kg.
Un problema similar es dado en brainly.com/question/24615636
Your answer is 500
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Answer: 64 fluid ounces
Step-by-step explanation:
Amount of water in the container = 128 fluid ounces
Amount drank by Toya every hour = 8 fluid ounces
For 8 hours, Toya would have drank:
= 8 × 8 fluid ounces
= 64 fluid ounces
To calculate the amount of fluid ounces
thataree in the container after 8 hours, we then subtract 64 fluid ounces from 128 fluid ounces. This will be:
= 128 fluid ounces - 64 fluid ounces
= 64 fluid ounces
48 = 4(x-2)
48 = 4x -8
56= 4x
14=x
x-2 = 12
one side is 12 inches long
The first is the correct
Δ ZYB ≈ Δ OWR by SSS
because:
ZB = OR = 5
ZY = OW = 3
YB = WR = 5.5
