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3 years ago

15

OK I need help on this one

1 answer:

Tasya [4]3 years ago

3 0

We wouldn't be able to do this for you because it's referring to YOUR town, not ours. If you're in public school, I'm sure they'd have similar answers than you - so it's hard to help here.

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Find the m<1 <br> 69<br> 71<br> 111<br> 86

Alexxandr [17]

Answer:

69

Step-by-step explanation:

m1 = 180 - (180 - 39 - 30) = 180 - 111 = 69

3 0

3 years ago

The numbers of beads on 500 handcrafted bead

pashok25 [27]

<span>The numbers of beads on 500 handcrafted bead necklaces follow a normal distribution whose mean is 24 beads and standard deviation is 4 beads.
</span>so....
<span>About 24 necklaces have more than 28 beads. </span>
<span>About 48 necklaces have more than 28 beads. </span>
<span>About 80 necklaces have more than 28 beads. </span>
About 96 necklaces have more than 28 beads<span>

</span> <span>About 80 necklaces have more than 28 beads.
</span><span>
Z score is 28-24/4=1
(1-.8413)=0.1587

500*0.1587=79.35~80

i did this like 2 or 3 years ago .</span>

7 0

3 years ago

In which interval is the graph constant?

SOVA2 [1]

Answer:

It is constant from point C to point D.

Step-by-step explanation:

7 0

3 years ago

Pls help math question i wil make brainliest

AVprozaik [17]

Answer:

(41/12)g+-23/12

Step-by-step explanation:

3(5g−1) /4 - (2g+7)/6

(15g-3)/4 - (2g+7)/6---> distributive property

3(15g-3)/12 - 2(2g+7)/12--->make the denominators same

(45g-9)/12 - (4g+14)/12---distributive property

7 0

3 years ago

aleksandr82 [10.1K]

Using the normal distribution, the probabilities are given as follows:

a. 0.4602 = 46.02%.

b. 0.281 = 28.1%.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

The parameters are given as follows:

$\mu = 959, \sigma = 263, n = 37, s = \frac{263}{\sqrt{37}} = 43.24$

Item a:

The probability is <u>one subtracted by the p-value of Z when X = 984</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{984 - 959}{263}$

Z = 0.1

Z = 0.1 has a p-value of 0.5398.

1 - 0.5398 = 0.4602.

Item b:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{984 - 959}{43.24}$

Z = 0.58

Z = 0.58 has a p-value of 0.7190.

1 - 0.719 = 0.281.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

8 0

2 years ago