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3 years ago

15

Stanley needs to purchase a cylindrical silo. He wants the radius to be 6 ft. The silo should hold 1700 cubic feet when full. Ho

w many feet tall must the slio be? Use 3.14 for Pi.

1 answer:

lubasha [3.4K]3 years ago

4 0

Answer:

15.03m

Step-by-step explanation:

h=V/πr2

h=1700/π·62

h≈15.0313

Hope that helps

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What is the answer for this? Please help... T[-4,5] (P) : (-2,1).

elena55 [62]

Answer:

I don't know hehehaha

Step-by-step explanation:

ibibmeth

8 0

3 years ago

Choose the table that represents g(x) = −2⋅f(x) when f(x) = x + 4

fomenos

Answer:

x g(x)

1 −10

2 −12

3 −14

Step-by-step explanation:

Substitute the values and do the arithmetic.

Table values for x are 1, 2, 3. We only need to find g(1) to determine which table is the correct choice.

f(1) = 1 +4 = 5 . . . . . . . . . put 1 where x is and do the arithmetic

g(1) = -2·f(1) = -2·5 = -10 . . . . . matches the 3rd choice

6 0

3 years ago

What is 0.69696969 expressed as the quotient of two integers in simplest form?

timofeeve [1]

When written as the quotient of two integers,

   0.69696969 = <em>69,696,969 / 100,000,000 .</em>

<u>If</u> you had said that the ' 69 ' keeps repeating forever and never ends,
then that decimal would represent the fraction
   23 / 33 .

3 0

3 years ago

Two researchers, Jaime and Mariya, are each constructing confidence intervals for the proportion of a population who is left-

soldi70 [24.7K]

Answer:

Jaime's. Interval not centered around the point estimate.

Step-by-step explanation:

When constructing a confidence interval based on a point estimate, the obtained point estimate must be the central value of the interval.

For Jaime's interval

Lower bound = 0.078

Upper Bound = 0.193

$Central = \frac{0.078+0.193}{2} =0.1355$

For Mariya's interval

Lower bound = 0.051

Upper Bound = 0.189

$Central = \frac{0.051+0.189}{2} =0.12$

For a point estimate of 0.12, only Mariya's interval is adequate since Jaime's is not centered around the point estimate.

4 0

3 years ago

Line RS bisects PQ at point R. Find RQ if PQ = 4 3/4

svetlana [45]

PQ is bisected by RS at R. It means that PRQ is a line segment with PR = RQ and each of half of PQ.

RQ = PQ/2 = 1/2 [ 4 3/4 ] = 1/2 * 19/4 = <em>19/8 </em> = 2 3/4

8 0

3 years ago

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