Answer:
1% of 800 is 8, while 2% of 800 is 16
Step-by-step explanation:
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Answer:
0 ≤ c ≤ 12
Step-by-step explanation:
The function can be rearranged to ...
p = 200c(12 -c) -4700
suggesting that revenue will be zero for a charge of 0 or for a charge of 12, and that fixed expenses are 4700. Charges less than 0 are uninteresting, and charges high enough to cause the number of customers to be negative also don't make any sense in this context.
Though out of the range of likely consideration, charges low or high enough to cause profit to be negative (more than 9.54, for example) seemingly can be reasonably modeled by this function.
This is a great question, but it's also a very broad one. Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.
In the case of vert. asy.: Set the denom. = to 0 and solve for x. Any real x values that result indicate the location(s) of vertical asymptotes.
Given:
The given equation is:
A line is perpendicular to the given line and passes through the point (4,-1).
To find:
The equation of required line.
Solution:
The slope intercept form of a line is:
Where, m is slope and b is y-intercept.
We have,
Here, the slope of the line is -4 and the y-intercept is 3.
Let the slope of required line be m.
We know that the product of slopes of two perpendicular lines is -1. So,
The slope of required line is and it passes through the point (4,-1). So, the equation of the line is:
Therefore, the equation of the required line is .
Answer:
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Step-by-step explanation:
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