Answer:
I. L = 10.35 feet
II. W = 93.15 feet.
Step-by-step explanation:
Let the length of the rectangle be L.
Let the width of the rectangle be W.
Given the following data;
Perimeter of rectangular field = 1700 feet
Translating the word problem into an algebraic expression, we have;
W = 9L
Mathematically, the formula for the perimeter of a rectangle is;
P = 2(L + W)
A. To write an equation;
X = P = 2(L + W)
B. To find the dimensions of the field;
207 = 2(L + 9L)
207 = 2L + 18L
207 = 20L
L = 207/20
L = 10.35 feet
To find the weight;
W = 9L
W = 9 * 10.35
W = 93.15 feet.
Therefore, the width of the field is
93.15 feet and the length of the field is
10.35 feet.
According to the secant-tangent theorem, we have the following expression:
Now, we solve for <em>x</em>.
Then, we use the quadratic formula:
Where a = 1, b = 6, and c = -315.
<h2>Hence, the answer is 15 because lengths can't be negative.</h2>
Answer:
your answer is B
Step-by-step explanation:
TeX rendering has been iffy at best on this site for the past few days, at least in my experience. I've attached a solution below.
Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.