I'm assuming that ? is a minus sign
3x+4y-8=0
a.
perpendicular lines have slopes that multiply to -1
ok
for ax+by-c=0
the slope is -a/b
so
3x+4y-8=0
slope=-3/4
perpendicular lines have slopes that multiply to get -1
-3/4 times what=-1
times both sides by -4/3
what=4/3
the slope is 4/3
y=mx+b
m=slope
b=y intercept
y=4/3x+b
we are given the point (2,3)
x=2 and y=3
3=4/3(2)+b
3=8/3+b
3-8/3=b
9/3-8/3=b
1/3=b
y=4/3x+1/3 is the equation
b. the slope is 4/3
c. the y intercept is 1/3
d. see attachment
Answer:
Domain: [1, 7]
Range: [-4, 2]
Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
Answer:

Step-by-step explanation:
General equation of a parabola that opens up is
, a>0
So equation becomes
which implies option A and option B can never be true for this parabola.
Also this parabola's vertex lies in 3rd quadrant where coordinates of both x and y will be negative.
So, the equation of parabola will be of the form 
Hence, option 4 that is
is correct.