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rewona [7]
3 years ago
15

In professional baseball, each team plays 160 games. After playing half their games, team A has won 60 and team B has won 49. If

team A wins half of its remaining games, how many of its remaining games must team B win to have the same number of wins as team A?
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0
The answer is 11 more wins
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Answer:

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Which of the following points would be a solution to this system of linear inequalities? ​
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Let's plug in both x and y values in the equation and check if the inequality is true...

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

(4,1) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 4 and y as 1

1 \leqslant 4 + 1 \\ 1 <  -  \frac{4}{2}  - 1

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\purple{ \rule{300pt}{3pt}}

(0, - 3) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 0 and y as -3

- 3 \leqslant 0 + 1 \\  - 3 <  -  \frac{0}{2}  - 1

- 3 \leqslant 1 \\  - 3 <  - 0 - 1

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6 0
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Answer:

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How this is possible.

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2) all the numbers from 5-9 are counted as the next number when rounded off.

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But numbers from 10-14 would never be rounded off to 20 instead they are rounded as 10.

Same happens in the hundreds case.

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Thus all the numbers ranging from 14,500 to 15444 would be rounded to 15000.

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