Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
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Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
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Answer:
x = -2
Step-by-step explanation:
Arrange 6x + y= -5, -6x + 12y=96 vertically:
6x + y= -5
-6x + 12y=96 Now combine like terms:
--------------------
13y = 91
Solving for y by dividing both sides by 13: y = 7
Find x by substituting 7 for y in the second equation: -6x + 12(7) = 96
Then -6x = -84 + 96, or:
-6x = 12, and so x = -2
Answer: 789.39
Step-by-step explanation: Just subtract 89.51 from 878.9.
Mark Brainliest if this helped!
Answer:
2 quarts of 100% antifreeze.
Step-by-step explanation:
5 quarts/ .40 * x/ 1
.40x= 5
x=2