A. the coordinates for the 3rd one is (7, -4)
There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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Answer:
The answer is "It would decrease, but not necessarily by 8%".
Step-by-step explanation:
They know that width of the confidence level is proportional to a confidence level. As just a result, reducing the confidence level decreases the width of a normal distribution, but not with the amount of variance in the confidence level. As just a result, when a person teaches a 90% standard deviation rather than a 98 percent normal distribution, the width of the duration narrows.
Answer:
perimeter of a square= 4 times square root of area
Answer:
Probability that the cost will be less than $500 is 0.95994 .
Step-by-step explanation:
We are given that Money magazine reported that a visit to a hospital emergency room for something as simple as a sore throat has a mean cost of $348 with a standard deviation of $87.
Let X = cost of a hospital emergency room visit for this medical service
So, X ~ N(
)
The standard normal z score distribution is given by;
Z = 
~ N(0,1)
(a) Probability that the cost will be less than $500 = P(X < $500)
P(X < 500) = P( < 
) = P(Z < 1.75) = 0.95994 {from z table}
Therefore, the probability that the cost will be less than $500 is 0.95994 .
