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Sonbull [250]
3 years ago
8

Which polynomial represents the sum below?

Mathematics
1 answer:
mart [117]3 years ago
5 0
=3x^6 +4x+3+3x^8+6x
Combine like terms
=3x^8+3x^6+(4x+6x)+3
=3x^8+3x^6+10x+3

C) 3x^8+3x^6+10x+3 is the answer.

Hope this helps! :)
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For her phone service , Rania pays a monthly fee of $ 18 , and an additional $0.06 per minute of use. The least she has been cha
pogonyaev

Answer:

I'm assuming we need to find the number of minute she as used. to do that we can right an inequality with m being the number of minutes

18+0.06m≥88.56

we then just solve this like we would with any other algebra equation, First we subtract 18 from both sides.

0.06m≥70.56

Then we dives by 0.06

m≥1176

Rania has used at least 1176 minutes

4 0
3 years ago
Jane made a poster that had a length: 1 2/3 of feet and a width: 5/6 of feet. What is the perimeter of her poster?
slamgirl [31]

Answer:

P   = 6 2/3 ft

Step-by-step explanation:

The formula for the perimeter of a rectangle of length L and width W is

P = 2(L + W).

Here the perimeter is P = 2(1 2/3 + 5/6) = 2(5/2 + 5/6)

                                                                  = 2(15/6 + 5/6) = 2(20/6)

                                                                  = 40/6 = 20/3

                                                              P   = 6 2/3 ft

5 0
2 years ago
Match the graph with the related table
sladkih [1.3K]
I believe the answer is C
6 0
2 years ago
Does someone know the answer to this <br> √7x+16+4=x
dalvyx [7]
I think it is 54.332
8 0
3 years ago
The population mean annual salary for environmental compliance specialists is about ​$62,000. A random sample of 32 specialists
lakkis [162]

Answer: 0.002718

Step-by-step explanation:

Given : The population mean annual salary for environmental compliance specialists is about ​$62,000.

i.e. \mu=62000  

Sample size : n= 32

\sigma=6200

Let x be the random variable that represents the annual salary for environmental compliance specialists.

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponds to x= 59000 will be :

z=\dfrac{59000-62000}{\dfrac{6200}{\sqrt{32}}}\approx\dfrac{-3000}{\dfrac{6200}{5.6568}}=-2.73716129032\approx-2.78

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than ​$59,000 :-

P(z

Hence, the probability that the mean salary of the sample is less than ​$59,000= 0.002718

3 0
3 years ago
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