At first we will find the slope of the line that <span>passes through the points A and B
</span>
<span>A ( -10,8), B(2,3)
slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12
the require line is parallel to the line </span><span><span>passes through the points A and B
</span>∴ the slope of the line </span><span>that passes through Point X = -5/12
and have a general form
y = m x + c
where m is the slope and c is constant
the constant can be calculated by substituting with the point x (-5,10) in the equation of general form
∴ 10 = (-5/12)*-5 + c
c = 10 - 25/12 = 95/12
∴ y = (-5/12)x +95/12 ⇒⇒⇒⇒ multiplying the equation by 12
∴ 12y = -5x +95
</span>
Answer:
4/5
Step-by-step explanation:
So first 180-70=110
second 360-110-90-90=360-290=70
Answer: 180 is the correct answer
2r²+15r-50
hope this helps
