1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sedbober [7]
3 years ago
12

What is the measure of ∠x?

Mathematics
2 answers:
Bond [772]3 years ago
7 0
It should be 105.

44 + 31 = 75

180 - 75 = 105.
goldenfox [79]3 years ago
5 0

Answer:

117+x=180°(sum of straight line)

Step-by-step explanation:

x=180-117

x=63

You might be interested in
Can someone answer this
bezimeni [28]

Answer:

Step-by-step explanation:

x         6         a

8       48        c  

-4        b       20

Let the unknown numbers of the multiplication grid are a, b and c.

1). 6 × 8 = 48

2). (-4)×6 = b

    b = -24

3). (-4) × a = 20

   a = -5

4). 8 × a = c

    8 × (-5) = c

    c = -40

Therefore, missing in the given multiplication grid are,

x         6        -5

8       48       -40  

-4      -24       20

6 0
3 years ago
Compute the number of ways to deal each of the following five-card hands in poker. 1. Straight: the values of the cards form a s
Elenna [48]

Answer:

The number of ways to deal each hand of poker is

1) 10200 possibilities

2) 5108 possibilities

3) 40 possibilities

4) 624 possibilities

5) 123552 possibilities

6) 732160 possibilities

7) 308880 possibilities

8) 267696 possibilities

Step-by-step explanation:

Straigth:

The Straight can start from 10 different positions: from an A, from a 2, 3, 4, 5, 6, 7, 8, 9 or from a 10 (if it starts from a 10, it ends in an A).

Given one starting position, we have 4 posibilities depending on the suit for each number, but we need to substract the 4 possible straights with the same suit. Hence, for each starting position there are 4⁵ - 4 possibilities. This means that we have 10 * (4⁵-4) = 10200 possibilities for a straight.

Flush:

We have 4 suits; each suit has 13 cards, so for each suit we have as many flushes as combinations of 5 cards from their group of 13. This is equivalent to the total number of ways to select 5 elements from a set of 13, in other words, the combinatorial number of 13 with 5 {13 \choose 5} .  However we need to remove any possible for a straight in a flush, thus, for each suit, we need to remove 10 possibilities (the 10 possible starting positions for a straight flush). Multiplying for the 4 suits this gives us

4 * ( {13 \choose 5} -10) = 4* 1277 = 5108

possibilities for a flush.

Straight Flush:

We have 4 suits and 10 possible ways for each suit to start a straight flush. The suit and the starting position determines the straight flush (for example, the straight flush starting in 3 of hearts is 3 of hearts, 4 of hearts, 5 of hearts, 6 of hearts and 7 of hearts. This gives us 4*10 = 40 possibilities for a straight flush.

4 of a kind:

We can identify a 4 of a kind with the number/letter that is 4 times and the remaining card. We have 13 ways to pick the number/letter, and 52-4 = 48 possibilities for the remaining card. That gives us 48*13 = 624 possibilities for a 4 of a kind.

Two distinct matching pairs:

We need to pick the pair of numbers that is repeated, so we are picking 2 numbers from 13 possible, in other words, {13 \choose 2} = 78 possibilities. For each number, we pick 2 suits, we have {4 \choose 2} = 6 possibilities to pick suits for each number. Last, we pick the remaining card, that can be anything but the 8 cards of those numbers. In short, we have 78*6*6*(52-8) = 123552 possibilities.  

Exactly one matching pair:

We choose the number that is matching from 13 possibilities, then we choose the 2 suits those numbers will have, from which we have 4 \choose 2 possibilities. Then we choose the 3 remaining numbers from the 12 that are left ( 12 \choose 3 = 220 ) , and for each of those numbers we pick 1 of the 4 suits available. As a result, we have

13 * 4 * 220 * 4^3 = 732160

possibilities

At least one card from each suit (no mathcing pairs):

Pick the suit that appears twice (we have 4 options, 1 for each suit). We pick 2 numbers for that suit of 13 possible (13 \choose 2 = 78 possibilities ), then we pick 1 number from the 11 remaining for the second suit, 1 number of the 10 remaining for the third suit and 1 number from the 9 remaining for the last suit. That gives us 4*78*11*10*9 = 308880 possibilities.

Three cards of one suit, and 2 of another suit:

We pick the suit that appears 3 times (4 possibilities), the one that appears twice (3 remaining possibilities). Foe the first suit we need 3 numbers from 13, and from the second one 2 numbers from 13 (It doesnt specify about matching here). This gives us

4 * 13 \choose 3 * 3 * 13 \choose 2 = 4*286*3*78 = 267696

possibilities.

7 0
3 years ago
Which of the following parabolas opens upward and appears narrower than y = −3x^2 + 2x − 1? A. y = 4x^2 − 2x − 1 B. y = −4x^2 +
Kamila [148]
Narrowing it down it's either a or c because the other 2 choices open downward (negative a).
Graphing the 2 parabolas choice c is narrower.
c
7 0
3 years ago
The ratio of the weight of an object on Planet A to the weight of the same object on Planet B is 100 to 3. If an elephant weighs
stiks02 [169]
150. Divide 5000 by 100 and you get 50. Multiply 3 by 50 and you get 150.
4 0
3 years ago
Read 2 more answers
Jay places $3200 in an investment account earning 4.1% interest compounded weekly. How much money would he have in the account a
jasenka [17]

Answer:

A = $3,926.71

Step-by-step explanation:

Given: Principal (P) = $3200, Annual Rate (R) = 4.1%, Time = 5 years

To find: How much money would he have in the account after 5 years, if he made no deposits or withdrawals during that time?

Formula: A = P(1 + r/n)^nt

Solution: Compound interest is one of the most important concepts to understand when managing your finances. It can help you earn a higher return on your savings and investments, but it can also work against you when you're paying interest on a loan

First, convert R as a percent to r as a decimal

r = R/100

r = 4.1/100

r = 0.041 rate per year,

Then solve the equation for A

A = P(1 + r/n)^{nt}

A = 3,200.00(1 + 0.041/12)^{(12)(5)}

A = 3,200.00(1 + 0.003416667)^{(60)}

A = $3,926.71

Hence, Jay would have $3,926.71 after 5 years is if he made no deposits or withdrawals during that time.

3 0
3 years ago
Other questions:
  • Solve equation 2+3x-1+4x=5x+1
    13·2 answers
  • Explain why numbers with a 5 in ones place or not prime numbers
    14·2 answers
  • NEED HELP ON THIS QUESTION ASAP
    8·2 answers
  • Question 1 (5 points): Consider the system of linear equations x1 − 4x2 − x4 = −7 x2 − 2x4 = 3 x4 + 2x5 = 3 (a) Write down the c
    12·1 answer
  • Each of 165 newly manufactured items is examined and the number of scratches per item is recorded (the items are supposed to be
    6·1 answer
  • Why does everyone keep an eye on Templeton?
    8·1 answer
  • Erica makes 4,840 monthly what is the maximum loan she can take out on a house?
    15·1 answer
  • Work out<br>a) 4/5 of 30​
    15·1 answer
  • A rule in a relation in which each input is paired with, or assigned to, exactly one output.
    14·1 answer
  • 25+30=15x+10x<br><br>solve for X​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!