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2 years ago

Solve by factoring. Check your answer.

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

4 0

Answer:

$x=0,4$

Step-by-step explanation:

Factor out the common terms from the given terms:

$x^2-4x=0$

You can factor out x from both:

$x(x-4)=0$

Rewrite, setting each equal to 0:

$(x)(x-4)=0\\\\x=0\\\\x-4=0$

Simplify the second equation by solving for x:

$x-4=0\\\\x-4+4=0+4\\\\x=4$

Therefore, x=0 or x=4

:Done

Virty [35]2 years ago

3 0

To factor, you split the equation so the factors multiply to get the whole equation.
(x-2)(x+2)

Then, interpret the factors.
The zeros can be found at (2,0) and (-2,0).
x=2, x=-2

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bekas [8.4K]

Answer:

-18

Step-by-step explanation:

-3x + x³

-3(-3) + (-3)³

9 + (-27)

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3 years ago

Read 2 more answers

Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = (x − a)(x − b). Describe

MatroZZZ [7]

Answer:

1) The parabola equation faces up

2) The y-intercept = a·b

3) The zeros are x = a and x = b

Step-by-step explanation:

1) The given information are;

f(x) = (x - a)·(x - b) which gives;

f(x) = x² - (b+a)·x + a·b

For an equation of the form a·x² - b·x + c, if a is positive, then the parabola faces up, therefore, the parabola equation, x² - (b+a)·x + ab where a is equivalent to +1 faces up

2) The y-intercept is given at x = 0, which gives;

f(0) = 0² - (b+a)·0 + a·b

The y-intercept = a·b

3) From f(x) = (x - a)·(x - b), when f(x) = 0, we have either;

(x - a) = 0 or (x - b) = 0

Therefore;

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3 years ago

Find the value of x for which the function y = x5-x³ + x² - 1 has a local minimum.

melisa1 [442]

The given function presents a local minimum in the coordinates (0,-1).

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization. One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

For solving this question, the given equation should be rewritten from the factoring.

$x^5-x^3+x^2-1=\left(x+1\right)^2\left(x-1\right)\left(x^2-x+1\right)=0$ . Then, you have 3 equations.

From the Zero Factor Principle, you can write

Equation 1

(x+1)²=0

x+1=0

x= -1

Equation 2

x-1=0

x=1

Equation 3

x²-x+1=0

$x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\ \\ x_{1,\:2}=\frac{-\left(-1\right)\pm \sqrt{3}i}{2\cdot \:1}$

From these points it is possible to plot a graph and you can see that the local minimum presents the coordinates (0,-1).