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Fiesta28 [93]
2 years ago
6

When does the t-distribution approach the standard normal distribution?

Mathematics
1 answer:
nirvana33 [79]2 years ago
7 0
Idk srry for not helpin
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When solving systems of equations with the elimination
viktelen [127]

Step-by step explanation:

That's a great question. Look for things such as these:

x=x (infinite solution)

x=12 (one solution)

x+3 = x + 5 (no solutions)

https://youtu.be/bq5gDsEdN3Q this video has more information, copy and paste the link into your search engine.

4 0
2 years ago
Plsss help meee :)))
lorasvet [3.4K]

Answer:

6*(-5)

Step-by-step explanation:

5 0
2 years ago
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10 Pts + Brainliest for the best answer
Sladkaya [172]

Answer:

BCG =65

Step-by-step explanation:

DCG + GCB = DCB

We know BCG = 31x+3 and GCD = 12x+2  and BCD = 91

Substituting these in

12x+2 + 31x+3 = 91

Combine like terms

43x +5 = 91

Subtract 5 from each side

43x+5-5 = 91-5

43x = 86

Divide by 43

43x/43= 86/43

x=2

BCG = 31x+3

        =31(2)+3

         =62+3

           =65

7 0
3 years ago
Read 2 more answers
The scores on an entrance exam to a university are known to have an approximately normal distribution with mean 65% and standard
emmasim [6.3K]

Answer:

The correct answer is - C. 24.1%

Step-by-step explanation:

Given:

mean μ = 65%

standard deviation δ = 7.1 %

solution:

Prob( X>70) = 1 - Prob(x<70)  

= P (x-μ/δ ≥ 70 -65/7.1)

= 1 - Prob( (70-65)/7.1)

= 1 - Prob ( z < 0.7042553)

= 0.24065

the percentage of students scoring 70 or more in the exam

= 24.065*100

= 24.1%

4 0
2 years ago
.............................................................
Anton [14]
Yes period ……….. lol
8 0
2 years ago
Read 2 more answers
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