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aleksklad [387]
3 years ago
14

What is the decimal equivalent to 4%?

Mathematics
2 answers:
professor190 [17]3 years ago
6 0

Answer:

0.8

Step-by-step explanation:

4/5 0.8 80%

hope this is useful

Komok [63]3 years ago
3 0

Hey!

------------------------------------------------

Solution and Explanation:

When you want to find the decimal of a number just divide by 100.

4 / 100 = 0.04

------------------------------------------------

Answer:

\large\boxed{0.04}

------------------------------------------------

Hope This Helped! Good Luck!

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zhenek [66]

Answer:

100

Step-by-step explanation:

428/4=107

107-7=100

8 0
3 years ago
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How do you find the g (acceleration due to gravity) in this question?
IRISSAK [1]
The weight (or mass) is irrelevant.

The period t = sqrt(2*pi*sqrt(l/g) where g is the acceleration due to gravity.

so t = 2*pi*sqrt(5/9.8) = 4.49 seconds.

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4 years ago
Part
olchik [2.2K]

Answer:

900 cubic inches.

Step-by-step explanation:

<u>Given the following data;</u>

Volume of right circular cone = 300in³

We know that the volume of a right circular cone is given by the formula;

V = \frac {1}{3} \pi r^{2}h

Where;

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  • h is the height of the right circular cone.

The volume of a right circular cylinder is given by the formula;

V = \pi r^{2}h

<em>Thus, multiplying the volume of the right circular cone by 3 would give us the volume of the right circular cylinder. </em>

V = \frac {1}{3} \pi r^{2}h * 3  

Substituting into the equation, we have;

V = 300 * 3

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4 0
3 years ago
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Step-by-step explanation:

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=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)

=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)

=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)

=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)

=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}

=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}

=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}

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