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3 years ago

What is the decimal equivalent to 4%?

Mathematics

2 answers:

professor190 [17]3 years ago

6 0

Answer:

0.8

Step-by-step explanation:

4/5 0.8 80%

hope this is useful

Komok [63]3 years ago

3 0

Hey!

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Solution and Explanation:

When you want to find the decimal of a number just divide by 100.

4 / 100 = 0.04

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Answer:

$\large\boxed{0.04}$

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Hope This Helped! Good Luck!

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Yo can someone help me out (READ CAREFULLY)

zhenek [66]

Answer:

100

Step-by-step explanation:

428/4=107

107-7=100

8 0

3 years ago

Read 2 more answers

How do you find the g (acceleration due to gravity) in this question?

IRISSAK [1]

The weight (or mass) is irrelevant.

The period t = sqrt(2*pi*sqrt(l/g) where g is the acceleration due to gravity.

so t = 2*pi*sqrt(5/9.8) = 4.49 seconds.

Frequency = 1/period = 0.223 Hertz.

5 0

4 years ago

Part

olchik [2.2K]

Answer:

900 cubic inches.

Step-by-step explanation:

Given the following data;

Volume of right circular cone = 300in³

We know that the volume of a right circular cone is given by the formula;

$V = \frac {1}{3} \pi r^{2}h$

Where;

V is the volume of right circular cone.

r is the radius of the base of the right circular cone.

h is the height of the right circular cone.

The volume of a right circular cylinder is given by the formula;

$V = \pi r^{2}h$

Thus, multiplying the volume of the right circular cone by 3 would give us the volume of the right circular cylinder.

$V = \frac {1}{3} \pi r^{2}h * 3$

Substituting into the equation, we have;

$V = 300 * 3$

V = 900in³

Therefore, the volume of a right cylinder that has the same base and height as the cone is 900 cubic inches.

4 0

3 years ago

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago

(All problems are connected with eachother.) Directions: Mr. Clark's backyard vegetable garden is circular, centered at point A,

jonny [76]

Check the picture below. part 1 and 2 are there.

part 3)

$\bf \textit{arc's length}\\\\
s=\cfrac{r\theta \pi }{180}\implies \cfrac{180s}{r\pi }=\theta \qquad 
\begin{cases}
\theta =\textit{angle in degrees}\\
r=radius\\
----------\\
s=12.2\\
r=\sqrt{\frac{315}{\pi }}
\end{cases}
\\\\\\
\cfrac{180\cdot 12.2}{\pi \sqrt{\frac{315}{\pi }}}=\theta \implies 69.8075^o\approx \theta \implies 70^o\approx\theta$

$\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=\sqrt{\frac{315}{\pi }}\approx 10\\
\theta \approx 70
\end{cases}\implies A=\cfrac{70\cdot \pi \cdot 10^2}{360}$

4 0

3 years ago