Answer:
F t = m Δv impulse delivered = change in momentum
Δv = 100 * .1 / .5 = 20 m/s original speed of puck
KE = 1/2 m v^2 = .5 * 20^2 / 2 = 100 J initial KE of puck
E = μ m g d energy lost by puck
Ff = μ m g = m a deceleration of puck due to friction
a = μ g = 9.8 * .2 = 1.96 m/s^2
v2 = a t + v1 = -1.96 * 4 + 20 = 12.2 m/s speed of puck on striking box
m v2 = M V conservation of momentum when puck strikes box
V = m v2 / M = 12.2 * .5 / .8 = 7.63 m/s speed of box after collision
KE = 1/2 M V^2 = .8 * 7.63^2 / 2 = 23.3 J KE of box after collision
KE = μ M g d energy lost by box in sliding distance d
d = 23.3 / (.3 * .8 * 9.8) = 9.91 m distance box slides
Sarcomere<span>The Sarcomere is the smallest functional unit of a myofibril (and also of the entire muscle) and contain the contractual elements between each pair of Z-discs.</span>
if we have to download something then probaly a virus
Explanation:
Given that,
Electric field, E = 7900 V/m
Magnetic field, 
(a) Let v is the velocity of a beam of electrons that goes undeflected when moving perpendicular to an electric and magnetic fields. The magnitude of electric force and the magnetic force balance each other as :
(b) Let r is the radius of the electron orbit. The radius of the motion of electron is given by :
Hence, this is the required solution.
30.) B and D seem to be the positive so basically the highest velocity. B starts from 0 to infinity and D starts from -1 to infinity because neither of those lines would meet, they would just continue forever growing. The two least would be A and C.
