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makvit [3.9K]
4 years ago
5

an 1800 kg car is approaching a stoplight at 15 m/s. what is the deceleration of the car if the brakes provide a stopping force

of 4520N
Physics
1 answer:
Mashcka [7]4 years ago
7 0
Using newton's second law, F = ma, the answer is -2.5 m/s^2.

4520 = (1800)(a)
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A current of 4 amps is running through a circuit with a resistance of 2ohms.What is the voltage.Show working
Rufina [12.5K]
Voltage = current * resistance
V = I*R
I = 4 A
R = 2 ohm
V = 4 A * 2 ohm
= 8 volt
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3 years ago
You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that emerges from this polarizer
kondor19780726 [428]

Answer:

The intensity of light from the first polarizer  is I_1  =  26 W/m^2

Explanation:

  The intensity of the unpolarized light is  I_o  =  52.0 \ W/m^2

   

Generally the intensity of light that emerges from the first polarized light is

            I_1  =  \frac{I_o}{2 }

 substituting values

             I_1  =  \frac{52. 0}{2 }

             I_1  =  26 W/m^2

5 0
3 years ago
The number of neutrons in an atom is determined by which if the following means?
LenKa [72]

The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus..

               

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5 0
3 years ago
Read 2 more answers
use the general formulas for gravitational force and centripetal force to derive the relationship between speed and orbital radi
MrRissso [65]

Answer:

v = \sqrt{\frac{GM}{r}}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{Mm}{r^{2}}  (1)                

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

The centripetal force can be found by means of Newton's second law:

F = ma  (2)

Since it is a circular motion, the acceleration can be defined as:

a = \frac{v^{2}}{r}  (3)

Where v is the velocity and r is the orbital radius.

Replacing equation (3) in equation (2) it is gotten:

F = m\frac{v^{2}}{r}  (4)

Hence,

m\frac{v^{2}}{r} = G\frac{Mm}{r^{2}}

Then, v can be isolated:

mv^{2} = G\frac{Mmr}{r^{2}}

mv^{2} = G\frac{Mm}{r}

v^{2} = G\frac{Mm}{mr}

v^{2} = \frac{GM}{r}

v = \sqrt{\frac{GM}{r}}

So the relationship between speed and orbital radius is given by the expression v = \sqrt{\frac{GM}{r}}

8 0
3 years ago
Some material consisting of a collection of microscopic systems is kept at a high temperature, so that all excited states are po
Lelechka [254]

Answer:

The responses to this question can be defined as follows:

Explanation:

During energy exchange E=hv, electrodes spring through one orbit to another

Please find the image file in the attachment.

Its absorption layer comprises 0.3 eV, 0.5 eV., 0.8 eV, 2.0 eV, 2.5 eV again, as light passes via material at low temperature those lines absorbed in the strata called absorption stratum.

6 0
3 years ago
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