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2 years ago

What causes competition among organisms?

Physics

1 answer:

dimaraw [331]2 years ago

5 0

Both organisms attempt to use the same limited sources

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What is the centripetal acceleration of a small laboratory centrifuge in which the tip of the test tube is moving at 19.0 meters

Artist 52 [7]

Answer: $3.61(10)^{3} \frac{m}{s^{2}}$

The centripetal acceleration $a_{c}$ of an object moving in a uniform circular path is given by the following equation:

$a_{c}=\frac{V^{2}}{r}$

Where:

$V=19m/s$ is the velocity

$r=10cm=0.1m$ is the radius of the circle

$a_{c}=\frac{(19m/s)^{2}}{0.1m}$

$a_{c}=3610m/s^{2}=3.61(10)^{3}m/s^{2}$

8 0

2 years ago

The mixture you separated was a mixture of iron filings, sand, and salt. Based on your understanding of matter, is this mixture

lianna [129]

homo. It is a mixture because it has different things in it. If they are distributed homogeneously ...

7 0

3 years ago

A pitot tube system measures the static pressure in 50 cm diameter duct containing air (\rho\:=rho =1.1 kg/m3) as 97 kPa and the

erastova [34]

Answer:

The velocity in duct is 73.854 m/s.

Explanation:

Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 $\frac{kg}{m^{3} }$ .

Also, P1 = Pressure in duct is 97kpa and P2 = Pressure at impact or stagnation point is 100kpa.

Using Bernoulli equation,

$P+\frac{1}{2}\rho v^{2} +\rho gh=0$

When air is flowing through duct,

$97,000+\frac{1}{2}\rho v^{2} +\rho gh1=0$

When air is at stagnation point.

$1,00,000+0+\rho gh1=0$

Comparing both the equation,

$97,000+\frac{1}{2}\rho v^{2} +\rho gh1=1,00,000+\rho gh1$

$\frac{1}{2}\rho v^{2}=3000$

$0.55v^{2}=3000$

$v^{2}=5454.54$

v=73.854 m/s.

Therefore, The velocity in duct is 73.854 m/s.

4 0

3 years ago

A single-slit diffraction pattern is formed on a distant screen. If the width of the single slit through which light passes is r

jarptica [38.1K]

Answer:

The width of the central bright fringe will increase

Explanation:

In a single-slit diffraction pattern, the distance of the nth-minimum from the central maximum on the screen is given by

$y=\frac{n \lambda D}{d}$

where

$\lambda$ is the wavelength of the wave

D is the distance of the screen from the slit

d is the width of the slit

The width of the central bright fringe is equal to twice the value of y=1 (first minimum), so:

$w=2 y(n=1) = \frac{2\lambda D}{d}$

And we see that it is inversely proportional to the width of the slit: therefore, if the width of the slit is reduced, the width of the central brigh fringe will increase.

5 0

3 years ago

A student, standing on a scale in an elevator at rest, sees that his weight is 997 N. As the elevator rises, the scale reads 122

Artyom0805 [142]

The total force F on the student is given by:

F = N - mg = ma

N normal force of the scale on to the student(scale readout)
m mass of the student
g acceleration due to gravity
a acceleration of the elevator

997 = mg
650 = m(g - a)

ma = 997 - 650
a = g(997 - 650)/997
a = 3,4

3 0

2 years ago