Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
Option C
Explanation:
Given -
Total number of initially marked lizards (M) 
Total number of recaptured lizards (C) 
Total number of recaptured marked lizards (R) 
As we know that -
We have to find "N" . "N" is the total population size of lizards in a 2-hectare plot in eastern Arizona.
Thus, on rearranging the above equation, we get -
Substituting the given values in above equation, we get -
Hence, option C is correct
The answer you are looking for is:<span>capillary beds</span>
I’m pretty sure males are ZZ. Let me know if I’m right and have a good rest of your day!
