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Free_Kalibri [48]
3 years ago
5

What is the value of x? 20 35 60 70

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0
Vertical angles are congruent. So, x+40=3x. 40=2x. 20=x.
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For 17a-17c, choose Yes or No to indicate wheter a zero must be written in the dividend to find the quotient.
Simora [160]

Answer:

a) yes b) no c) no

Step-by-step explanation:

In order to know this, remember something: to do the division between a number and a rational number like this and with zero to the left, the best way to solve them is converting these number to a natural number.

To do that, you only need to multiply the number by 10, 100, 1000, depending of how many decimals it have.

In case a) 0.05 has two decimals, therefore we multiply by 100:

0.05 * 100 = 5

However, when you do that, you have to do the same thing with the number in the dividend, in this case, 1.4:

1.4 * 100 = 140

So we can conclude that 1.4 you have to add a zero to do the division.

Case b) and c) do not apply, in both cases we multiply by 10 and we get this:

25.2 and 6,

26.1 and 3.

8 0
3 years ago
WILL GIVE BRAINLIEST TO PERSON WHO ANSWERS
Tpy6a [65]
A² - 225 = (a-15)(a+15)
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7 0
3 years ago
Can someone help please ?
MAVERICK [17]

Answer:

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7 0
3 years ago
Find the greatest common factor.
jonny [76]

Answer:

Greatest is the multiplication exponent by algebra times by the quotient

Step-by-step explanation:

8 0
3 years ago
How many ways can a person select 3 coins from a box consisting of a penny, a nickel, a dime, a quarter, a half dollar, and a on
tekilochka [14]

Answer:

A person can select 3 coins from a box containing 6 different coins in 120 different ways.

Step-by-step explanation:

Total choices = n = 6

no. of selections to be made = r = 3

The order of selection of coins matter so we will use permutation here.

Using the formula of Permutation:

                  nPr = \frac{n!}{(n-r)!}

We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.

Order of coin is important means that if we select 3 coins in these two orders:

--> nickel - dime - quarter

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They will count as two different cases.

Calculating the no. of ways 3 coins can be selected from 6 coins.

nPr = \frac{n!}{(n-r)!} = \frac{6!}{(6-3)!}

nPr = 120

6 0
3 years ago
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