Software as a service that is the answer to your question.Hope this helps!!
Answer:
Step-by-step explanation:
First, the acceleration of gravity is -9.8m/s^2. This still works out since the formula uses 1/2 of it.
Hopefully you see where the other parts come from. Anyway, standard form of a quadratic is ax^2+bx+c=0. So this is almost there. You just need to subtract that 2.1 from both sides.
-4.9t^2+7.5t+-.3=0
Now with this, since it has taken into account the height that the ball was caught with that 2.1, you just need to find the 0s, which is what the quadratic equation does.
The quadratic equation is (-b±sqrt(b^2-4ac))/(2a) and we have a = -4.9, b = 7.5 and c = -.3. Remember you want to keep the signs. Now we just plug in.
(-b±sqrt(b^2-4ac))/(2a)
(-7.5±sqrt((-7.5)^2-4*-4.9*-.3))/(2*-4.9)
(-7.5±sqrt(56.25-5.88))/(.9.8)
(-7.5±sqrt(50.37))/(-9.8)
(-7.5±7.097)/(-9.8)
The plus or minus means there are two equations.
(-7.5+7.097)/(-9.8) and (-7.5-7.097)/(-9.8) So we will solve for both of these.
.04112 and 1.4895. That means these two times are when the ball is at 2.1 meters. One time on the way up and one time on the way down. We can safely assume that the other player catches the ball on the way down, so we want to use the second time, so 1.4895 seconds.
Answer: See explanation
Step-by-step explanation:
You didn't give the options but let me help out. We are told that a certan tile pattern had 6 triangles for every 20 squares.
The ratio that represents an equivalent ratio will be:
6 : 20 = 6/20 = 3/10 = 3:10
Simplify the expression.
5x+6y+ 16
a) Is the twitch - initial positive twitch or sudden movement, which is what
makes the car jolt into action.
b) is the acceleration - graph shows the acceleration and
deceleration of the car.
c) is the velocity - starts at 0 and increases until the car
travels at its right speed.
d) is the position - assuming that the car is going on only
one direction. This graph is the only one that does not go back to the x-axis.
