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LenaWriter [7]
3 years ago
9

20 POINTS. PLZ HELP!!!!!

Mathematics
1 answer:
liberstina [14]3 years ago
8 0

Answer:

x=27

Step-by-step explanation:

Notice that Angle A is being bisected.

Hence, we can use the Angle Bisector Theorem to write the following proportion:

\frac{x+8}{10}=\frac{2x-5}{14}

Solve for x. Cross-multiply:

10(2x-5)=14(x+8)

Distribute:

20x-50=14x+112

Subtract 14x from both sides:

6x-50=112

Add 50 to both sides:

6x=162

Divide both sides by 6. Hence, the value of x is:

x=27

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Solve to simpilist form 3/4/2 . (3 on top of 4/2) :D
Georgia [21]

Answer:

5/1

Step-by-step explanation:

5 0
3 years ago
Shade the grid to represent the ratio. Then find the missing number.<br><br> 11/20 = __/100
Lemur [1.5K]

Answer: The missing number is 55

The denominators are 20 and 100. We multiply by 5 to jump from the smaller denominator to the larger.

Do the same for the numerators

11*5 = 55

Or you can solve the proportion below for x

11/20 = x/100

11*100 = 20*x

1100 = 20x

20x = 1100

x = 1100/20

x = 55

4 0
3 years ago
Solve for y.<br><br> −2y+7=−5
kakasveta [241]

Answer:

Ur right! The answer is y = 6

Step-by-step explanation:

So, we have the equation of -2y + 7 = -5.

So, if y = 6, it would now be (-2 * 6) + 7 = -5.

Now, lets solve:

(-2 * 6) + 7

-12 + 7

= -5

So, ur answer is A. y = 6.

Hope this helps :DD

5 0
2 years ago
Read 2 more answers
If the term of arthematic progression decrease in magnitude then common difference must be
Tpy6a [65]

We can say that if the term of arithmetic progression decrease in magnitude then the common difference must be <u>negative</u>.

An arithmetic progression is a sequence where every term is a sum of the previous term and a common difference.

If we suppose the first term of an arithmetic progression to be a, and the common difference to be d, then the arithmetic progression goes like this:

The first term, a₁ = a,

Second term, a₂ = a₁ + d = a + d,

Third term, a₃ = a₂ + d = a + 2d,

Fourth term, a₄ = a₃ + d = a + 3d, and it goes so on up to,

The n-th term, aₙ = aₙ₋₁ + d = a + (n - 1)d.

In the question, we are asked if the term of arithmetic progression decrease in magnitude then what can we say about the common difference.

As the magnitude of the term decreases, we can show that as:

The n-th term < The first term,

or, aₙ < a₁,

or, a + (n - 1)d < a,

or, a + (n - 1)d - a < a - a {Subtracting a from both sides},

or, (n - 1)d < 0.

Since, n > 1, (n - 1) > 0, thus we get the common difference, d < 0, that is, the common difference is negative.

Thus, we can say that if the term of arithmetic progression decrease in magnitude then the common difference must be <u>negative</u>.

Learn more about arithmetic progressions at

brainly.com/question/6561461

#SPJ4

8 0
2 years ago
Four time the sum of twice a number and six is thirty-two. Find the number
Andrei [34K]

Answer:

4(2x+6)=32  x= 1

Step-by-step explanation:

multiply 4 to 2x and 6=   (8x+24)=32

then subtract 24 from 32 = 8

then divide 8 from both sides

8x/8=8/8

x=1

8 0
3 years ago
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