I am thinking that the correct answer among the choices presented is option D. The points lie on the line equidistant from the endpoints of AB. <span>The points lie on the line that is the perpendicular-bisector of segment AB. </span>Hope this answers your question.
y - y₁ = m(x - x₁)
y - (-7) = -1¹/₅(x - (-3))
y + 7 = -1¹/₅(x + 3)
y + 7 = -1¹/₅(x) - 1¹/₅(3)
y + 7 = -1¹/₅x - 3³/₅
![m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-17 - (-2)}{3 - (-9)} = \frac{-17 + 2}{3 + 9}} = \frac{-15}{12} = \frac{-5}{4} = -1\frac{1}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_%7B2%7D%20-%20y_%7B1%7D%7D%7Bx_%7B2%7D%20-%20x_%7B1%7D%7D%20%3D%20%5Cfrac%7B-17%20-%20%28-2%29%7D%7B3%20-%20%28-9%29%7D%20%3D%20%5Cfrac%7B-17%20%2B%202%7D%7B3%20%2B%209%7D%7D%20%3D%20%5Cfrac%7B-15%7D%7B12%7D%20%3D%20%5Cfrac%7B-5%7D%7B4%7D%20%3D%20-1%5Cfrac%7B1%7D%7B4%7D)
y - y₁ = m(x - x₁)
y - (-2) = -1¹/₄(x - (-9))
y + 2 = -1¹/₄(x + 9)
y + 2 = -1¹/₄(x) - 1¹/₄(9)
y + 2 = -1¹/₄x - 11¹/₄
- 2 - 2
y = -1¹/₄x - 13¹/₄
y - y₁ = m(x - x₁)
y - (-3) = ⁻¹/₄(x - 8)
y + 3 = ⁻¹/₄(x) + ¹/₄(8)
y + 3 = ⁻¹/₄x + 2
- 3 - 3
y = ⁻¹/₄x - 1
y - y₁ = m(x - x₁)
y - (-17) = ¹/₂(x - (-6))
y + 17 = ¹/₂(x + 6)
y + 17 = ¹/₂(x) + ¹/₂(6)
y + 17 = ¹/₂x + 3
- 17 - 17
y = ¹/₂x - 14
![m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-4 - 8}{-4 - 6} = \frac{-12}{-10} = \frac{12}{10} = \frac{6}{5} = 1\frac{1}{5}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_%7B2%7D%20-%20y_%7B1%7D%7D%7Bx_%7B2%7D%20-%20x_%7B1%7D%7D%20%3D%20%5Cfrac%7B-4%20-%208%7D%7B-4%20-%206%7D%20%3D%20%5Cfrac%7B-12%7D%7B-10%7D%20%3D%20%5Cfrac%7B12%7D%7B10%7D%20%3D%20%5Cfrac%7B6%7D%7B5%7D%20%3D%201%5Cfrac%7B1%7D%7B5%7D)
y - y₁ = m(x - x₁)
y - 8 = 1¹/₅(x - 6)
y - 8 = 1¹/₅(x) - 1¹/₅(6)
y - 8 = 1¹/₅x - 7¹/₅
+ 8 + 8
y = 1¹/₅x + ⁴/₅
Answer:
x = 115 - p
Step-by-step explanation:
generally in algebra you will use the letter "x" to represent a value you do not know, so it wants an algebraic expression for "p subtracted from 115", this can be rewritten as 115 - p. So the unknown value "x" is equal to 115 - p.
Answer:
31, 32 and 33
Step-by-step explanation:
Mark these consecutive integers as (n-1), n and (n+1)
(n-1) is the smallest of them
Now write the equation
10 * (n-1) = 3 * (n-1 + n + n+1) + 22
10n - 10 = 3 * (n + n + n) + 22
10n - 10 = 3 * 3n + 22
10n - 10 = 9n + 22
10n - 9n = 22 + 10
n = 32
Now find these three integers
n-1 = 32 - 1 = 31
n = 32
n+1 =32 + 1 =33
The answer for " J " would be 228