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2 years ago

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please help i rly need it my math teacher gave me over 30 assignments and a project that are all due tomorrow today and i want t

o sewer slide

1 answer:

Sedaia [141]2 years ago

8 0

Answer:

x= -14

Step-by-step explanation:

-14 subtracted by 2 is -16, since its absolute it means its positive, meaning its 16 greater than 14, I may be wrong so just to let you know. Depends on how the teacher wants it to be.

You might be interested in

What is the value of z, rounded to the nearest tenth? Use the law of sines to find the answer. 2. 7 units 3. 2 units 4. 5 units

worty [1.4K]

The law of sine is the nothing but the relationship between the sides of the triangle to the angle of the triangle (oblique triangle).

The value of the $z$ is 3.2 (rounded to the nearest tenth). The option 2 is the correct option.

<h3>What is law of sine?</h3>

The law of sine is the nothing but the relationship between the sides of the triangle to the angle of the triangle (oblique triangle).

It can be given as,

$\dfrac{\sin A}{a} =\dfrac{\sin B}{b} =\dfrac{\sin C}{c}$

Here $A,B,C$ are the angle of the triangle and $a,b,c$ are the sides of that triangle.

Given information-

The triangle for the given problem is attached below.

In the triangle the base of the triangle is 2.6 units long.

The sine law for the given triangle can be written as,

$\dfrac{\sin X}{x} =\dfrac{\sin Y}{y} =\dfrac{\sin Z}{z}$

As the value of $y$ side is known and the value of $z$ has to be find. Thus use

$\dfrac{\sin Y}{y} =\dfrac{\sin Z}{z}$

Put the values,

$\dfrac{\sin 51}{2.6} =\dfrac{\sin 76}{z}$

Solve it for the $z$ ,

$z=\dfrac{\sin 76\times 2.6}{\sin 51}\\z=3.2462$

Hence the value of the $z$ is 3.2 (rounded to the nearest tenth). The option 2 is the correct option.

Learn more about the sine law here;

brainly.com/question/2264443

4 0

2 years ago

Problem: The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72

Lisa [10]

Answer:

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

1) 0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2) 0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3) 0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4) 0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

Step-by-step explanation:

To solve these questions, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The height, X, of all 3-year-old females is approximately normally distributed with mean 38.72 inches and standard deviation 3.17 inches.

This means that $\mu = 38.72, \sigma = 3.17$

Sample of 10:

This means that $n = 10, s = \frac{3.17}{\sqrt{10}}$

Compute the probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

This is 1 subtracted by the p-value of Z when X = 40. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{40 - 38.72}{\frac{3.17}{\sqrt{10}}}$

$Z = 1.28$

$Z = 1.28$ has a p-value of 0.8997

1 - 0.8997 = 0.1003

0.1003 = 10.03% probability that a simple random sample of size n= 10 results in a sample mean greater than 40 inches.

Gestation periods:

$\mu = 266, \sigma = 16$

1. What is the probability a randomly selected pregnancy lasts less than 260 days?

This is the p-value of Z when X = 260. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{260 - 266}{16}$

$Z = -0.375$

$Z = -0.375$ has a p-value of 0.3539.

0.3539 = 35.39% probability a randomly selected pregnancy lasts less than 260 days.

2. What is the probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less?

Now $n = 20$ , so:

$Z = \frac{X - \mu}{s}$

$Z = \frac{260 - 266}{\frac{16}{\sqrt{20}}}$

$Z = -1.68$

$Z = -1.68$ has a p-value of 0.0465.

0.0465 = 4.65% probability that a random sample of 20 pregnancies has a mean gestation period of 260 days or less.

3. What is the probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less?

Now $n = 50$ , so:

$Z = \frac{X - \mu}{s}$

$Z = \frac{260 - 266}{\frac{16}{\sqrt{50}}}$

$Z = -2.65$

$Z = -2.65$ has a p-value of 0.0040.

0.004 = 0.4% probability that a random sample of 50 pregnancies has a mean gestation period of 260 days or less.

4. What is the probability a random sample of size 15 will have a mean gestation period within 10 days of the mean?

Sample of size 15 means that $n = 15$ . This probability is the p-value of Z when X = 276 subtracted by the p-value of Z when X = 256.

X = 276

$Z = \frac{X - \mu}{s}$

$Z = \frac{276 - 266}{\frac{16}{\sqrt{15}}}$

$Z = 2.42$

$Z = 2.42$ has a p-value of 0.9922.

X = 256

$Z = \frac{X - \mu}{s}$

$Z = \frac{256 - 266}{\frac{16}{\sqrt{15}}}$

$Z = -2.42$

$Z = -2.42$ has a p-value of 0.0078.

0.9922 - 0.0078 = 0.9844

0.9844 = 98.44% probability a random sample of size 15 will have a mean gestation period within 10 days of the mean.

8 0

2 years ago

If 3/5 of a number is 42,what is the twice number

JulsSmile [24]

Answer:

140

Step-by-step explanation:

Let the number be represented by x. You are given ...

(3/5)x = 42

Multiplying by 10/3 gives ...

(10/3)(3/5)x = (10/3)(42)

2x = 140 . . . . the value of twice the number

3 0

2 years ago

Read 2 more answers

What are the square numbers between 99 and 199

Inessa05 [86]

100 (10)
121 (11)
144 (12)
169 (13)
196 (14)

7 0

2 years ago

Read 2 more answers

-5 >3 true or false plssssss answer

Ivan

Answer:

false

Step-by-step explanation:

-5 is smaller than 3 not bigger.

8 0

2 years ago