Explanation:
Given that,
Mass of the car, m₁ = 1250 kg
Initial speed of the car, u₁ = 7.39 m/s
Mass of the truck, m₂ = 5380 kg
It is stationary, u₂ = 0
Final speed of the truck, v₂ = 2.3 m/s
Let v₁ is the final velocity of the car. Using the conservation of momentum as :
So, the final velocity of the car is 2.5 m/s but in opposite direction. Hence, this is the required solution.
<span>The actual time to travel would be 200 miles / 60 miles/hour = 3.33333 hours or 3 hours and 20 minutes. Since the van driver has been directed to allow an extra hour, the amount of time allowed should be 4 hours and 20 minutes for the total duration of the trip to Dallas.</span>
Answer:
speed of molecule ∝ 1/mass of molecule.
Explanation:
The velocities of the molecules depend on their masses. That's because if the molecules are large in size, their velocity is slower. Therefore their velocity is quicker when their size is small, since the molecules can move faster.
Therefore , it can be written as
speed of molecule ∝ 1/mass of molecule.
<span>Answer:
F = ma
Fx = max
WHERE:
Fx = forces in the x direction
m = mass
ax = acceleration in the x direction
If we look at the figure, there are only two forces in the x direction. The first force is the x component force 4.0 N acting to the right, denoted as +4.0 N. The second force is the 2.0 N force acting to the left, denoted as -2.0 N.
Fx = max
4.0 N - 2.0 N = (7.8 kg)*ax
2.0 N = (7.8 kg)*ax
ax = 0.25641 m/s^2
Because the question is asking you to write it to two significant figures,
==>ax = 0.26 m/s^2</span>
Answer:
20 J
Explanation:
Given:
Weight of the book is,
Height or displacement of the book is,
The work done on the book to raise it to a height of 2 m on a shelf is against gravity. The gravitational force acting on the book is equal to its weight. Now, in order to raise it, an equal amount of force must be applied in the opposite direction.
So, the force applied by me should be equal to weight of the body and in the upward direction. The displacement is also in the upward direction.
Now, work done by the applied force is equal to the product of force applied and displacement of book in the direction of the applied force.
Therefore, work done is given as:
Therefore, the work done to raise a book to a height 2 m from the floor is 20 J.