Complete Question
Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?
Answer:
Go-cart A is faster
Explanation:
From the question we are told that
The length of the track is ![l = 1.0 \ km = 1000 \ m](https://tex.z-dn.net/?f=l%20%3D%20%201.0%20%5C%20km%20%20%3D%20%201000%20%5C%20%20m)
The speed of A is ![v__{A}} = 20 \ m/s](https://tex.z-dn.net/?f=v__%7BA%7D%7D%20%3D%20%2020%20%5C%20m%2Fs)
The uniform acceleration of B is ![a__{B}} = 0.333 \ m/s^2](https://tex.z-dn.net/?f=a__%7BB%7D%7D%20%3D%20%200.333%20%5C%20m%2Fs%5E2)
Generally the time taken by go-cart A is mathematically represented as
=> ![t__{A}} = \frac{1000}{20}](https://tex.z-dn.net/?f=t__%7BA%7D%7D%20%3D%20%5Cfrac%7B1000%7D%7B20%7D)
=> ![t__{A}} = 50 \ s](https://tex.z-dn.net/?f=t__%7BA%7D%7D%20%3D%20%2050%20%5C%20%20s)
Generally from kinematic equation we can evaluate the time taken by go-cart B as
![l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2](https://tex.z-dn.net/?f=l%20%3D%20%20ut__%7BB%7D%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%20a__%7BB%7D%7D%20%2A%20t__%7BB%7D%7D%5E2)
given that go-cart B starts from rest u = 0 m/s
So
![1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2](https://tex.z-dn.net/?f=1000%20%3D%20%200%20%2At__%7BB%7D%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%20%2A%200.333%20%20%2A%20t__%7BB%7D%7D%5E2)
=>
=>
Comparing
we see that
is smaller so go-cart A is faster
Answer:
Given:
m=1000kg
u= 16.7m/s
v=0m/s
F=8000N
Required:
s=?
Solution:
F=m × a
8000N=1000kg × a
a=8m/s^2
Since it decelerate a= -8m/s^2
v^2 = u^2 + 2as
s=v^2 - u^2 / 2a
s= 0 - (16.7m/s)^2 / 2 × -8m/s^2
s= -278.89/-16
s= 17.43m
The car travels approximately 17.43m before it stops
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Answer:
B = 0.546 T, F = 2.59 10⁻¹² N
Explanation:
The magnetic force is
F = q v x B
We can calculate the magnitude of the force and find the direction by the right hand rule
F = q v B sin θ
Let's use Newton's second law
F = m a
Acceleration is centripetal
a = v² / r
We substitute
q v B sin θ = m v² / r
The angle between the field and the radius of the circle is 90º so sin 90 = 1
q B = m v / r
B = m v / q r
Let's calculate ’
B = 1.67 10⁻²⁷ 2.97 10⁷ / (1.60 10⁻¹⁹ 0.568)
B = 0.546 T
The foce is
F = q v B
F = 1.60 10⁻¹⁹ 2.97 10⁷ 0.546
F = 2.59 10⁻¹² N
The specific heat of a metal or any element or compound can be determined using the formula Cp = delta H / delta T / mass. delta pertains to change. That is change in enthalpy and change in temperature. From the given data, Cp is equal to 343 cal per (86-19) c per 55 grams. This is equal to 0.093 cal / g deg. Celsius
Because of the magnets are actually electromagnetics aka what causes them to repel each other the atoms and the electrons will make a force of them pushing away from each other because the two magnetic poles are not north and south