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makvit [3.9K]
3 years ago
11

An immersion heater of power J= 500 W is used to heat water in a bowl. After 2 minutes, the temperature increases from T1= 85°C

to T2 = 90°C. The heater is then switched off for an additional minute, and the temperature drops by Estimate the mass of the water in the bowl. The thermal capacity of water c = 4.2 x 103 J K-1 Kg-1
Physics
1 answer:
Setler79 [48]3 years ago
4 0

Answer: 0.051kg

Explanation:

Using the law of calorimetry which states that the amount of heat lost by a hot substance is equal to the amount of heat gained by the cold substance.

Applying the law to this question,

Amount of heat lost by the heater = heat gained by the water

Heat lost by Immersion heater Q1 = Power×time

Given power = 500W time = 2minutes = 120seconds

Heat loss by immersion heater = 500×120 = 60,000Joules

Heat gained by water = mc∆t where;

m is the mass of the water in the bowl = ?

c is the specific heat capacity = 4.2x10³JK-1 Kg-1

∆t = change in temperature = 90°C -85°C = 5°C

= 273+5 = 278K

Substituting in the formula we have;

Q2= 4.2×10³×278×m = 1,167,600m

According to the law if calorimetry,

Q2=Q1

1,167,600m = 60000

m = 60000/1,167,600

m = 0.051kg

Therefore the mass of water in the bowl is 0.051kg

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A boat having stones floats in water. If stones are unloaded in water, what will happen to the level of water?​
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A subway train starts from rest at a station and accelerates at a rate of 1.68 m/s2 for 14.2 s. It runs at constant speed for 68
liubo4ka [24]

Answer:

total distance = 1868.478 m

Explanation:

given data

accelerate = 1.68 m/s²

time = 14.2 s

constant time = 68 s

speed = 3.70 m/s²

to find out

total distance

solution

we know train start at rest so final velocity will be after 14 .2 s is

velocity final = acceleration × time      ..............1

final velocity = 1.68 × 14.2

final velocity = 23.856 m/s²

and for stop train we need time that is

final velocity = u + at

23.856 = 0 + 3.70(t)

t = 6.44 s

and

distance = ut + 1/2 × at²     ...........2

here u is initial velocity and t is time for 14.2 sec

distance 1 = 0 + 1/2 × 1.68 (14.2)²

distance 1 = 169.37 m

and

distance for 68 sec

distance 2= final velocity × time

distance 2= 23.856 × 68

distance 2 = 1622.208 m

and

distance for 6.44 sec

distance 3 = ut + 1/2 × at²

distance 3 = 23.856(6.44) - 0.5 (3.70) (6.44)²

distance 3 = 76.90 m

so

total distance = distance 1 + distance 2 + distance 3

total distance = 169.37 + 1622.208 + 76.90

total distance = 1868.478 m

7 0
3 years ago
Read 2 more answers
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