True.
Conductivity is the ability to transmit heat, electricity or sound. Conductivity is a physical property.
A physical property is one which can be measured or observed without changing the composition or identity of a the substance.
Conductivity is a physical property because the composition of the substance does not change.
A copper wire is still a copper wire when it is conducting electricity. Like wise, an aluminum rod is still an aluminum rod when heated. It is conducting heat but the heat does not change it, it is still an aluminum rod during the whole process.
In a constant acceleration of 3m per second, after 10 seconds,
3 x 10 = 30
B. 30m/s is your answer
hope this helps :D
I believe it would be 1.6 East
Answer:
Explanation:
Theoretical efficiency = T₁ - T₂ / T₁ where T₁ and T₂ is absolute temperature of hot and cold end of the heat engine.
= 600 / (273 + 700 )
= 600 / 973
= .6166
operating efficiency = 40% of .6166
= .4 x .6166
= .2466 = 24.66 %
efficiency = work output / heat input
= 5000 / heat input = .2466
heat input = 5000 / .2466
= 20275.75 J .
HEAT EXTRACED = 20275.75 J.
Height of the waterfall is 0.449 m
its horizontal distance will be 2.1 m
now let say his speed is v with which he jumped out so here the two components of his velocity will be


here the acceleration due to gravity is 9.81 m/s^2 downwards
now we can find the time to reach the other end by y direction displacement equation


also from x direction we can say


now we have

we will plug in this value into first equation



now as we know that

t = 0.63 s


so his minimum speed of jump is 4.1 m/s