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Contact [7]
3 years ago
8

What is the answer.. 1+3*3-52+43×0 = ??

Mathematics
2 answers:
Anton [14]3 years ago
4 0
<h2>The awnser to your question is -42. Hope this helps!</h2>

-Ella

zepelin [54]3 years ago
3 0

1 + 3 x 3 - 52 + 43 x 0 = -42

Hope this helps

-AaronWiseIsBae

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The sum of this is -9
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A deep-sea diver dives from the surface to 131 feet below the
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Answer:

146 feet below the surface

Step-by-step explanation:

-131+8-18-28+23=-146

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1 year ago
PLZ ANSWER ASAP WILL GIVE 50PTS if u explain and mark brainliest!!!!!!!
Vinil7 [7]

Answer:

Step-by-step explanation:

1.

\frac{5q+5p}{2} = 3+4p\\5q+5p = 6+8p \\5q = 6 +3p \\q = \frac{6+3p}{5}    ( a=3,b=6,c=5)

2. q-p = 3p +5

q = 4p+5

4p = q-5

p = (q-5)/4

3. y = 2a -bx^{2}

bx^{2} = 2a - y \\\\x^{2} = \frac{2a - y}{b} \\x = \sqrt{\frac{2a-y}{b}}

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2 years ago
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What is the sum of the terms of the series (−1) + (−2) + (−3) + . . . + (−10)?
Murrr4er [49]
You can solve this problem by using the Gauss method. The Gauss method is a method where you can add the first and last numbers together, and then multiply by how many times that appears. Here, the sum of the first and last number is -11. In this sequence, it would appear ten times (since there are ten terms and the terms are used twice in every eleven). -11 * 5 is -55, so that means the answer to this question is -55. 
8 0
3 years ago
The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0
3 years ago
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