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3 years ago

Find the sum of 16+22+28+...+112

Mathematics

1 answer:

Elodia [21]3 years ago

6 0

Im not 100 percent positive that this is correct but I think the answer is
184

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Jacob has some cookies. 3/4 of his cookies are chocolate chip. Out of the chocolate chip cookies 1/8 of them have nuts as well.

ryzh [129]

Well, we can find the answer by multiplying the two fractions. 3/4*1/8 equals 3/32.

7 0

4 years ago

Read 2 more answers

.A square field has a side 30m. Find the cost of fencing its four sides at Rs. 10 per metre

Ratling [72]

Answer:

1,200

Step-by-step explanation:

So first we need to find the perimeter

$P=30+30+30+30\\\\P=120$

so it costs 10 per meter

$120\times 10=1,200$

7 0

3 years ago

Explain why the function of f(x)=4x^2+8x is neither even or odd

myrzilka [38]

Answer:

By putting x = -x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

Step-by-step explanation:

We need to explain why the function of $f(x)=4x^2+8x$ is neither even or odd

First we will understand, when the function is even and odd

Even function:

<em>A function is even if f(-x) = f(x) </em>

Odd function:

<em>A function is odd if f(-x) = -f(x) </em>

So, if we get the above result by putting x = -x, then we can say that the function is even or odd.

If we don't get any of the above results then the function is neither even nor odd.

So, for the given function: $f(x)=4x^2+8x$

Put x = -x

$f(x)=4x^2+8x\\Put x=-x\\f(-x)=4(-x)^2+8(-x)\\f(-x)=4x^2-8x$

So, by putting x=-x in f(x) i.e. f(-x) we didn't get f(x) or -f(x) so, the function is neither even nor odd.

6 0

3 years ago

Is this statement true or false -7 -2 > 6 - 14

exis [7]

Answer:

false

Step-by-step explanation:

(-7-2) > (6-14)

-7-2 = -9

6-14 = -8

-9 is not > -8, because -9 is farther to the left on a number line. So, this statement would be false.

6 0

3 years ago

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

Read 2 more answers