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maw [93]
2 years ago
13

Expand the following numbers 62,336,003

Mathematics
1 answer:
madreJ [45]2 years ago
8 0

Answer:

6×10^(7)+2×10^(6)+3×10^(5)+3×10^(4)+6×10^(3)+3

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At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a
morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = \dfrac{15}{120}=0.125

As we know the poisson process, we get that

P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda

So, for exactly one car would be

P(n=1) is given by

=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

0.2599\times 18=4.6798

We will find the traffic flow q such that

P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%

Hence, a) 4.6798, and b) 19.8%.

7 0
3 years ago
What is 10 times 90 divided by -19
Semenov [28]
10 times 90 is 900, and divided by -19 is -900/19.
5 0
3 years ago
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Solve the system by substitution. <br> -5x+3y=2 <br> Y=2x
Volgvan

Answer:

2 is the required answer.

Step-by-step explanation:

<u>Solution:</u>

<u>Given</u><u>:</u>

-5x+3y=2..............(i)

Putting the value of y=2x in the equation (i); we get:

i.e -5x+3×2x=2

or, -5x+6x=2

or, x=2

i.e. x=2

y=2x=2×2=4

8 0
3 years ago
16+64846 what is the answer
astra-53 [7]
64,862 is the answer.
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A car completes a journey in 10 minutes. For the first half of the distance the speed was 60km/h and for the second half the spe
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100km long thats how long the journey was
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