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Amanda [17]
3 years ago
9

A store sells paint sets. Each paint set costs the same amount. During a sale, the store reduces the price of each paint set by

$1.50. Logan spends
$13.47 on 3 paint sets at the sale price.
What was the price of I paint set before the sale?
Mathematics
1 answer:
Tom [10]3 years ago
3 0

Answer:

the price of I paint set before the sale was $5.99

Step-by-step explanation:

Selling price of 3 paint sets = $13.47

To get selling price of 1 set

we divide both LHS and RHS by 3

Selling price of 3/3 = 1 paint sets = $13.47/3 = $4.49

Thus, selling price of 1 paint set after sale  is $4.49

Given that

the store reduces the price of each paint set by $1.50

Let the price before sale be x

selling price of 1 paint set after sale =  price before sale - $1.50

$4.49 = $x - $.150

$x = $4.49 + $1.50 = $5.99

Thus, the price of I paint set before the sale was $5.99

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Step-by-step explanation:

Given:

Number of players    Height range

4                                     66-67

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Answer:

x = 36.3°

using tane rule:

\sf tan(x)= \dfrac{opposite}{adjacent}

Here!

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=============

\hookrightarrow \sf tan(x) = \dfrac{22}{30}

\hookrightarrow \sf x= tan^{-1}(\dfrac{22}{30} )

\hookrightarrow \sf x= 36.253^{\circ \:}

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