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Anon25 [30]
4 years ago
14

In the Dobzhansky–Muller model, an ancestral population (aabb) splits into two lineages. Different mutations produce different n

ew alleles in each population (Aabb in one population, aaBb in the other). All of the following genotypes would be viable except:
1. aabb
2. Aabb
3. aaBB
4. AaBb
5. aaBb
Biology
1 answer:
enyata [817]4 years ago
4 0

All the genotype except aabb  would be viable.

Explanation:

The Dobzhansky model refers to the incompatibility of genes among species. The population of ancestral species was of the AABB genotype. But it is further divided into two populations.

One population involves a and A and the other has b and B. It has been found that the a and b are incompatible mutually. There is no presence of interaction between them in the actual species. So, the first genotype would not be viable in this model.

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