Answer: 44g
Step-by-step explanation:
Half life refers to the length of time it takes for half of the atoms of the element in question to decay.
The half life here is 1 minute which means that in a minute, the amount of protactinium left would be:
= 352 / 2
= 176g
After the second minute:
= 176 / 2
= 88g
After the third minute:
= 88 / 2
= 44g
She has made 28 snowflakes.
<span><span><span>82</span>=64</span><span><span>82</span>=64</span></span>choices for that.
Now, for the second one, we can't be in the row or column of that first one, so leaving us with <span><span><span>72</span>=49</span><span><span>72</span>=49</span></span> choices.
Then so on, we have <span><span><span>62</span>=36</span><span><span>62</span>=36</span></span> for the third one, <span>2525</span> for the fourth one, and so on <span>……</span>
But, however, we have to remember the rooks are not labeled, thus it doesn't matter specifically about a specific rook's position.
Thus, we have a total of <span><span><span><span>(8!<span>)2</span></span><span>8!</span></span>=40320</span><span><span><span>(8!<span>)2</span></span><span>8!</span></span>=40320</span></span> ways.
Answer:
65*
Step-by-step explanation:
All angles in a triangle = 180 degrees.
Answer:
The sample size needed if the margin of error of the confidence interval is to be no more than 0.02.
n= 2015
Step-by-step explanation:
Given the customer relations department will survey a random sample of customers and compute a 95% confidence interval for the proportion that are dissatisfied
Given data from past studies, they believe that this proportion will be about 0.28
The proportion of success(p) = 0.28
We know that the margin of error of 95% of intervals of given proportion
margin of error = …(i)
Given margin of error = 0.02
Substitute values in equation (i) cross multiplication √n
0.02 √n = 2√0.28X0.72
On calculation, we get √n = 44.89
squaring on both sides, we get
n = 2015
<u>Conclusion</u>:-
The sample size needed if the margin of error of the confidence interval is to be no more than 0.02.
n= 2015