Answer:
B
Step-by-step explanation:
y³=64
![y=(64)^{\frac{1}{3} } =\sqrt[3]{64}](https://tex.z-dn.net/?f=y%3D%2864%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B64%7D%20)
Answer:
-20,476
Step-by-step explanation:
51 x 8 = 408
It can be in this way: 51*8=408
You can set up a systems of equations to solve this problem.
The equation y = 2x-3 represents the father's age where y = The father's age and x = The son's age.
The equation 30=y-x represents the difference between the two ages.
In order to be able to solve a system, the two equations can be in the same form. (They don't need to be it's just easier for me to have them in the same form) One is in standard form (ax+by= c) and the other one is in slope intercept form (y=mx+b where m is the slope and b is the y- intercept).
Lets put the equation y=2x-3 into standard form.
y=2x-3
+3 +3
y+3=2x
-y -y
3=2x-y
We have the two equations 30=y-x and 3=2x-y
Now to solve the system.
30=y-x
3=2x-y or 3=-y+2x
30=y-x
3=-y+2x The -y and y cancel each other out since they are the same term but are the inverse of each other one is neg one is pos.
Your left with
30=-x Now you just combine the two equations. 30+3 and 2x-x
3=2x
33=x The son's age is 33. To Find the Fathers age we would just plug 33 for x into one of the equations to find the Fathers age.
SON'S AGE IS 33
Answer:
Each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.
Step-by-step explanation:
The amount spent on supplies is $20.
The number of cookies baked is = 50.
If the profit to be made is more than $25.00 .
Then we can safely say that all the cookies have to be sold for
= $20.00 + $25.00
= $45.00
Therefor the required inequality can be written as
50 x ≥ $45.00 ⇒ x ≥ 
⇒ x ≥ $0.90.
Therefore we can say that each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.
