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3 years ago

I need some help on this. Anyone know how to do this ?????

Mathematics

1 answer:

melisa1 [442]3 years ago

7 0

S:side
hyp:hypotenuse(side facing 90°)

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Associations In Data:Question 10

Karo-lina-s [1.5K]

Answer:

$\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9$

$|62-78.9| = 16.9$

$|63-78.9| = 15.9$

$|68-78.9| = 10.9$

$|72-78.9| = 6.9$

$|79-78.9| = 0.1$

$|80-78.9| = 1.1$

$|83-78.9| = 4.1$

$|93-78.9| = 14.1$

$|94-78.9| = 15.1$

$|95-78.9| = 16.1$

$MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}$

And replacing we got:

$MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12$

And the best anwer is

10.12

Step-by-step explanation:

We have the following data given:

62 63 68 72 79 80 83 93 94 95

And we need to begin finding the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = \frac{62+63+68+72+79+80+83+93+94+95}{10}= 78.9$

Now we can find the mean absolute deviation like this:

$|62-78.9| = 16.9$

$|63-78.9| = 15.9$

$|68-78.9| = 10.9$

$|72-78.9| = 6.9$

$|79-78.9| = 0.1$

$|80-78.9| = 1.1$

$|83-78.9| = 4.1$

$|93-78.9| = 14.1$

$|94-78.9| = 15.1$

$|95-78.9| = 16.1$

And finally we can find the mean abslute deviation with the following formula:

$MAD = \frac{\sum_{i=1}^n |X_i -\bar X|}{n}$

And replacing we got:

$MAD =\frac{16.9+15.9+10.9+6.9+0.1+1.1+4.1+14.1+15.1+16.1}{10}= 10.12$

And the best anwer is

10.12

8 0

4 years ago

Commutative property

goldfiish [28.3K]

Simply put, it says that the numbers can be added in any order, and you will still get the same answer. For example, if you are adding one and two together, thecommutative property<span> of addition says that you will get the same answer whether you are adding 1 + 2 or 2 + 1. This also works for more than two numbers.</span>

8 0

3 years ago

I’m not sure how to do this

Cerrena [4.2K]

It's b because you have to round up

5 0

3 years ago

Read 2 more answers

Need the work for this. 192 is the answer

Art [367]

Replace x with 3:

y = -3 *4^3