Answer:1. Pyruvate carboxylase
2. Phosphoenol pyruvate carboxy kinase
Explanation:
The conversion of pyruvate to phosphoenol pyruvate is catalyzed by two enzymes Pyruvate carboxylase and phosphoenol pyruvate carboxy kinase
1. Pyruvate carboxylase reaction
Pyruvate in the cytoplasm enters the mitochondria. Then, carboxylase of pyruvate to oxaloacetate is catalysed by a mitochondrial enzyme, pyruvate carboxylase. It needs the co-enzymes biotin and ATP.
The oxaloacetate formed has to be transported from the mitochondrial to the cytosol because further reaction of gluconeogenesis are taking place in cytosol.
2. Phoaphoenol pyruvate carboxy kinase (PEPCK)
In the cytoplasm, PEPCK enzyme then converts oxaloacetate to phoaphoenol pyruvate by removing a molecule of CO2. GTP or ITP donates the phosphate group.
The net effect of these two reactions is the conversion of pyruvate to phoaphoenol pyruvate. This circumverts the irreversible step in glycolysis catalyzed by pyruvate kinase (step 9 if glycolysis)
Answer :Four characteristics were to be used for the classification of all viruses:
Nature of the nucleic acid in the virion.
Symmetry of the protein shell.
Presence or absence of a lipid membrane.
Dimensions of the virion and capsid.
Explanation:
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Answer:
1
Explanation:
"Six carbon dioxide molecules (CO2) are required to create one glucose molecule (C6H12O6) because carbon dioxide has one carbon per molecule, while glucose molecules have six carbons."
Answer:
It will take 63 years
In 189 years, one-eight of the sample will be left
By multiplying the number of half-life cycles
Explanation:
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