Question

Find the solutions of the equation.

Answer 1

Assignment: $\bold{Solve \ Equation: \ x^2-4x-5=0}$

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Answer: $\boxed{\bold{x=5,\:x=-1}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Solve With Quadric Formula

Note: $\bold{For\:a\:quadratic\:equation\:of\:the\:form\ ax^2+bx+c=0}$

$\bold{the \ solutions \ are \ x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}}$

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$\bold{a=1,\:b=-4,\:c=-5:\quad x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:1\left(-5\right)}}{2\cdot \:1}}$

[ Step Two ] Simplify Expressions

$\bold{\frac{-\left(-4\right)+\sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}: \ 5}$

$\bold{\frac{-\left(-4\right)-\sqrt{\left(-4\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}: \ -1}$

[ Step Three ] Combine Solutions

$\bold{x=5,\:x=-1}$

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$\bold{\rightarrow Mordancy \leftarrow}$