X=-9
There is no slope in either equation. Therefore, x=-11 and x=-9 will be two vertical and parallel lines at (-11,0) and (-9,0)
Answer:
x=12, y=6
Step-by-step explanation:
Very simple!
Just substitute 0 for y and solve for x!
(anything times 0 equals 0!)

Now you can do the same thing but substitute 0 for x!


Hope this helps!
Answer:
5
Step-by-step explanation:
slope = (difference in y)/(difference in x)
subtract the y-coordinates: 5 - 0 = 5
subtract the x-coordinates in the same order: 3 - 2 = 1
Divide the difference in y by the difference in x.
slope = 5/1 = 5
Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Three diagonals can be drawn in a hexagon mmyyy dude.