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2 years ago

When the population mean and standard deviation are known, what distribution is used for the analysis of the sample?.

Mathematics

1 answer:

Kitty [74]2 years ago

7 0

When the population mean and standard deviation are known, you use the standard normal distribution

<h3>How to determine the distribution?</h3>

There are several probability distributions; these include

Normal distribution
Poisson distribution
Chi square distribution
Binomial distribution
Etc

Of all these distribution, only the standard normal distribution can be used when the population mean and standard deviation are known,

Note that it is also referred to as the z-distribution

Read more about probability distributions at:

brainly.com/question/24756209

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Use addition to solve the linear system of equations. Include all of your work in your final answer. $\left\{ \right.$ 3x-y=6

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Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

$3x-y=6 \\y=x-4$

We can write second equation y=x-4 as: $-x+y=-4$

Let:

$3x-y=6--eq(1)\\ -x+y=-4--eq(2)$

Now, Adding equation 1 and 2

$3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1$

So, we get x = 1

Now, put value of x in second equation to find value of y:

$y=x-4\\Put\:x=1\\y=1-4\\y=-3$

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

4 0

3 years ago

The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F

OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

$\frac{(1 -0.99)}{2}=0.005$

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

$n=\frac{z^2pq}{e^2}$

Where, e is the margin of error,

Substitute the respective values.

$n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89$

Hence, the Sample size is 1918.89035

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3 years ago

Please Help

Vinil7 [7]

Answer:

1.2

Step-by-step explanation:

You simply have to look for a point on the graph that has an x-coordinate of -6. Only one is (-6. 1.2), so 1.2 is your answer.

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3 years ago

24. Find the slope and y-intercept of the line.<br> Y=7/5x-3

Ad libitum [116K]

Answer:

slope = m = 7/5

y-intercept = b = -3

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

y = 7/5 x - 3

slope = m = 7/5

y-intercept = b = -3

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2 years ago

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Here is a list of numbers.<br> 32 29 30 37 34 33 31 Work out the median

andrew11 [14]

Answer:

20, 29, 30, 31, 32, 33, 34, 37

~ the median is: 31 +32 / 2 = 31.5

Step-by-step explanation:

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3 years ago

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