All categories

3 years ago

Please help me!! 50 points!!!

Mathematics

2 answers:

myrzilka [38]3 years ago

6 0

Answer:

I notice that all of these chips look very delicious. I wonder if they taste as delicious as they look. this image reminds me of geometric triangles in math class and my family all think that it looks phenomenal and yummy and spicy and delicious

Thepotemich [5.8K]3 years ago

5 0

Answer:

I notice that it looks like a bunch of tiny triangles. I wonder why there is only one chip with hot on it. It reminds me of a pie chart used to write down data.

Step-by-step explanation:

hope that helps you :)

You might be interested in

Write a rule for the function that shifts every point in the plane 10 units down and 4 units to the right

ElenaW [278]

Answer:

Substitute y with y+10 and x with x-4.

Step-by-step explanation:

To shift every point in the plane 10 down you have to substitute y with y+10 and to shift every point in the plane 4 units right you have to substitute x with x-4.

Suppose the origin of function on the plane is (0,0) now we have to make the origin (4,-10).

first (x,y)=(0,0)

When we substitute x and y

(x-4,y+10)=(0,0)

x-4=0

x=4

y+10 = 0

y= -10

Now the origin is (4,-10).

Hence the function is shifted 10 units down and 4 units right.

8 0

3 years ago

How is the sum expressed in sigma notation? 11 + 17 + 23 + 29 + 35 + 41

Ann [662]

<h3>The sum expressed in sigma notation is:</h3>

$11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i$

Solution:

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

Thus the series goes on like this:

5 + 6(n) , where n = 1 to 6

This can be expressed in sigma notation as:

$11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n$

We can expand the sigma notation and verify the results

$\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41$