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patriot [66]
3 years ago
13

Estimate the value of 50.75 times 0.18

Mathematics
2 answers:
Elena L [17]3 years ago
4 0
9.14.
392.8
175.4. Hope it helps!


Elenna [48]3 years ago
3 0
<span>Estimate the value of 50.75 times 0.18.  Round off 50.75 to 50 and 0.18 to 0.2.  

Then the approximate product is 10.  

The exact answer is 9.135.  



9.9^2 times 1.79 could be approx'd by  10^2 times 1.8, or 180.

</span>
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Write a compound inequality to represent the following verbal expression:
EastWind [94]

Answer:

21≤X<28

Or

X≥21+X<28

Step-by-step explanation:

Both equations mean the same thing

7 0
3 years ago
The graph of a linear equation contains the points (3,11) and (-2,11). Which point also lies on the graph?(YOU MUST SHOW WORK)
dexar [7]
Y= ax+b

when x=3, y=11   and when x= -2, y=11
          3a+b=11
          -2a+b=11    | * -1
3a+b=11
2a-b=-11
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  5a=0, a=0:5, a=0
⇒ b=11
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So ( 1,11)  or (2,11) are also points on the graph
3 0
3 years ago
Help help hep math math
MrRissso [65]

300 {ft}^{2}

Step-by-step explanation:

d=20

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7 0
2 years ago
Read 2 more answers
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
2 years ago
Factoring 2m^2 + 10m+25
oksian1 [2.3K]
Oh...........sorry?
///
5 0
3 years ago
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